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Harlamova29_29 [7]
2 years ago
7

If y varies directly as x and y = 8 when x = 4, what is the value of y when x = 16? a. 32 b. 16 c. 64 d. 28

Mathematics
1 answer:
ddd [48]2 years ago
5 0

By finding the proportional relation between x and y, we will see that when x = 16, we have y = 32.

<h3>How to get the value of y when x = 16?</h3>

If y varies directly with x, then we can write the relation as:

y = k*x

Where k is the constant of proportionality.

First, we know that when x = 4, we have y = 8, replacing that we get:

8 = k*4

Solving for k, we get:

k = 8/4 = 2.

Then the relation between x and y is:

y = 2*x

When x = 16, we have:

y = 2*16 = 32

Then the correct option is a.

If you want to learn more about proportional relations:

brainly.com/question/12242745

#SPJ1

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3 years ago
Determine the standard variation of the data below. (1, 2, 3, 4, 5)
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Then, we calculate for the summation of the squares of differences of these numbers from the mean, S
 
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Divide this summation by the number of items and take the square root of the result to get the standard deviation.

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8 0
3 years ago
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A girl can run 6 2/3 metres in one second. How long will it take her to run 100 metres?
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Answer:

15 seconds

Step-by-step explanation:

How did i get this answer? It is apparent that the girl is capable of running 6 2/3 metres per one second and she must run 100 metres.

First, let's convert 2/3 into a decimal so that it is easier to calculate later. 2/3=0.667 (you can also just do 2 divide by 3 and will end up with the same number)

Now our numbers are 6.667 and 100. Let's divide 100 by 6.667 which estimates to 15

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2 years ago
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