Answer:
18.04% probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given time interval.
Suppose the mean number of deviations and incursions per year at the Los Angeles International Airport (LAX) is 2.
This means that 
Find the probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year
This is P(X = 3).
18.04% probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year
If the length of JK is 16.4 miles, it will be diameter of this circle, the radius will be JK/2 = 8.2 miles
As we know the length of circle is 2π*r in this case r = 8.2
The arc JM is 1/4 length of the whole circle so arc JM = (2π*8.2)*(1/4) = 2π*8.2/4 = π*8.2/2 = π*4.1
if we assume that π=3.14 the answer will be 3.14 * 4.1 = 12.874.... And as the answer needs to be rounded to the nearest tenth it will be 12.874≈12.9
So the answer will be 12.9
Count by 1s or 5s. Write the first five numbers you would count, starting at 15.Starting by 1s
1. 16
2. 17
3. 18
4. 19
5. 20
Next is by 5s
1. 20
2. 25
3. 30
4. 35
5. 40
Your answer is ≈ 19
Step-by-step explanation:
180 - 124 = 56
56 / 3 = 18.66666666666667
18.66666666666667 round it up...…
19
X = 19
<em>Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Have a wonderful day!</em>
<span>square roots of 49/121
=</span><span>square roots of 7^2/11^2
= 7/11</span>
