this can be solve using newtons heating of cooling
(Ts – T) =(Ts – To)*e^(-kt)
Where Ts is the ambient temperature
To is initial temperature
T is the temperature at time t
t is the time
k is constant
fisrt solve the constant k for the given first scenario
(99 – 36) = (99 – 46)*e(-5k)
K = -0.0346
Using k, solve T at t = 13 min
(99 – 46) = (99 – T)*e(-13*(-0.0346)
T = 58.82 degree F
Answer:
= $20
Step-by-step explanation:
Simple interest is given by the formula'
Interest = PRt/100, where P is the principal amount, R is the rate of interest and t is the interest period in years
Therefore;
Simple interest = ($ 1000 × 2 × 1)/100
= $ 20
The simple interest owed for the use of the principal at a period of 1 year is $ 20.
<span>4a+7b+3a-2b+2a
Substitute all of the variables for the numbers given
4(-5)+7(3)+3(-5)-2(3)+2(-5)
Multiply all of the variables by their coefficient
-20+21-15-6-10
Combine like terms
Final Answer: -30
</span>
Answer:what it is
Step-by-step explanation:
