4x2-36=0
+36 +36
4x2=36
Divide by 4
X2=9
Square root of x2 is x and the square root of 9 is 3
X=3
Hey there! I'm happy to help!
Here's José's equation.
J=2a+15
And here is Nancy's.
N=3a+5
We want to find the number of animals where they are the same amount, or where J=N. We can write these equations as equal and solve for a to find the answer!
2a+15=3a+5
Subtract 15 from both sides.
2a=3a-10
Subtract 3a from both sides.
-a=-10
Divide both sides by -1.
a=10
Therefore, José and Nancy charge the same amount for 10 animals.
Have a wonderful day! :D
Hello from MrBillDoesMath!
Answer:
One example is 52 and 54. They are between 50 and 60 and have the factor 2 in common
Discussion:
Consider the numbers between 50 and 60:
51, 52, 53, 54, 55, 56, 57, 58, 59
53 and 59 are primes so they don't have any factors in common and we can focus on the other numbers in the range.
Consider 52. It's even so is divisible by 2 as are 54, 56, 58. So 52 and 54 , for example, are are two number between 50 and 60 that have the factor 2 in common
Even number are visible by 2. Let's look for numbers visible by 3. How about 54 ( = 18 *3) and 57 ( = 19*3)? That works so its looks like there are many answers to this question.
Thank you,
MrB
No, because the sum of any of the sides must be greater than all sides. 5.6 +4.0=9.6 which is less than 10.6, meaning that it is impossible to create a triangle with those lengths.
Answer:
it is C
Step-by-step explanation: