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4 years ago

How do i solve 5x +100=10x

Mathematics

2 answers:

joja [24]4 years ago

7 0

5x+100=10x
-5x on both sides (10x-5x=5x)
100=5x
divide by 5 on both sides (100/5= 20)
20=x

My name is Ann [436]4 years ago

3 0

First, you can rewrite the equation as 5x-10x=-100. You need to do this so that you can carry “x” to one side in order to solve it. Thus, 100 becomes -100 because you’re carrying it to the other side. Then, you subtract. 5x-10x is -5x. Now your equation is -5x=-100. Divide both sides by -5, so that you remove the negative and the coefficient. -100/-5 is 20. This, x is equivalent to 20. You can check your work by substituting the value 20, instead of “x”.

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Step-by-step explanation:

Mrs. Kim is teaching a 5th grade class

She is standing 48 feet in front of Lester
Carey is sitting to Lester's right
Carey and Mrs. Kim are 50 feet apart

We need to find how far apart Lester and Carey

Look to the attached figure

The positions of Mrs. Kim, Lester, and Carey formed a right triangle

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∴ The length of the hypotenuse of the Δ = 50 feet

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∴ The length of one leg of the Δ = 48 feet

The formula of length of the sides of the right Δ is:

$(hypotenuse)^{2}=(leg_{1})^{2}+(leg_{2})^{2}$

Substitute the length of the hypotenuse and the length of the given leg in the formula above

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Learn more:

You can learn more about the right triangle in brainly.com/question/1238144

#LearnwithBrainly

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