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2 years ago

Seismology In 1812, an earthquake of magnitude 7.9 shook New Madrid,

1 answer:

8 0

I think it’s 39.81. I don’t know if that was the answer to YOUR question but I’m pretty sure that’s comparing the energy

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The difference of the square of a number and three times the sum of the number and 7 is more than the product of that number and

Pachacha [2.7K]

Answer:

x2 - 3(x + 7) > 15x

x2 - 3x - 21 > 15x

6 0

3 years ago

What is the value of X? (giving brainliest and thanks to all!)

Jlenok [28]

Answer:

I believe it is A

Step-by-step explanation:

I dont quite remember the formula, but I belive that 30 would be correct because if im remembering correctly the formulas are "a + b = c" and "c - (a/b) = (a/b)

a/b = a or b, depending what they give you

4 0

2 years ago

Read 2 more answers

Stuck on this question. Help appreciated!!

marta [7]

Answer:

the missing is 4.98

Step-by-step explanation:

4 0

3 years ago

If angle∠ A and angle∠ B are supplementary angles and angle∠ A is eighteight times as large as angle∠ B, find the measures of a

Shalnov [3]

A = 8B
A + B = 180
8B + B = 180
9B = 180
B = 20
A = 8 * 20 = 160

4 0

3 years ago

Assume that trees are subjected to different levels of carbon dioxide atmosphere with 7% of the trees in a minimal growth condit

taurus [48]

Answer: The mean and standard deviation are 567.2 and 89.88 resp.

Step-by-step explanation:

Since we have given that

For 370 parts per million = 7% = 0.07

For 440 parts per million = 10% = 0.10

For 550 parts per million = 49% = 0.49

For 670 parts per million = 34% = 0.34

So, Mean of the carbon dioxide atmosphere for these trees would be

$E[x]=370\times 0.07+440\times 0.1+550\times 0.49+670\times 0.34=567.2$

And

$E[x^2]=370^2\times 0.07+440^2\times 0.1+550^2\times 0.49+670^2\times 0.34=329794$

So, Variance would be

$Var\ x=E[x^2]-E[x]^2=329794-567.2^2=8078.16$

So, the standard deviation would be

$\sigma=\sqrt{8078.16}=89.88$

Hence, the mean and standard deviation are 567.2 and 89.88 resp.

3 0

3 years ago