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Orlov [11]
2 years ago
13

PLZ HELP,ANSWER WHAT IS IN THE PICTURE

Mathematics
1 answer:
MrMuchimi2 years ago
3 0

Answer: X'(-3, -2), Y'(-5, 1), and Z'(2, -3)

Step-by-step explanation:

Upon reflection across the x-axis, the x-coordinates remain the same while the signs of the y-coordinates flip. So, the coordinates will be X(3, -2), Y(5, 1), and Z(-2, -3).

Upon reflection across the y-axis, the signs of the x-coordinates will flip while the signs of the y-coordinates remain the same. So, the coordinates will be X′(-3, -2), Y′(-5, 1), and Z′(2, -3).

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mote1985 [20]

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sin(2\theta)=2*sin(\theta)*cos(\theta)

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cos^2(\theta)+sin^2(\theta)=1\\sin^2(\theta)=1-cos^2(\theta)\\sin(\theta)=\sqrt{1-cos^2(\theta)} \\sin(\theta)=\sqrt{1-(\frac{3}{18} )^2}\\sin(\theta)=\sqrt{1-\frac{9}{324} }\\sin(\theta)=\sqrt{\frac{324-9}{324} }\\sin(\theta)=\sqrt{\frac{315}{324} }\\\\sin(\theta)=\frac{3}{18}\sqrt{35 }

With this information, we can now complete the value of the sine of the double angle requested:

sin(2\theta)=2*sin(\theta)*cos(\theta)\\sin(2\theta)=2*\frac{3}{18} \,\sqrt{35} \,\frac{3}{18}\\sin(2\theta)=\frac{2*3*3}{18*18}\,\sqrt{35} \\sin(2\theta)=\frac{\sqrt{35} }{18}

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