Question

Solve the following equations for 0 ≤ theta ≤ 360º cosec(2 — 45°) = 2​

Answer 1

Step-by-step explanation:

here ,

$cosec \alpha = \frac{1}{ \sin( \alpha ) }$

now,

cosec(2-45°)=2

or,

1/sin(2-45°) =2

or,

1/sin2cos45°-cos2sin45=2

or,

$\frac{1}{ \sin(2) \frac{1}{2} - \cos(2) \frac{1}{2} } = 2$

or,

sorry I have that much qualifications to work on this question and hoping this much will make bit easy for you to solve it further