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3 years ago

5

I need to know the answer to this question

1 answer:

Lana71 [14]3 years ago

4 0

Answer:

6= 15 1/3

Step-by-step explanation:

8 + 6=14

1/2=5/10

3/5=6/10

6/10+5/10=11/10=1 1/2

14+1 1/2= 15 1/2

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NEED HELP AGAIN

Viefleur [7K]

2238 - 300 = 1938 ft is your answer

6 0

2 years ago

Find the volume of the sphere.

Volgvan

Step-by-step explanation:

v=4/3*π*r^3

v=4/3*22/7*(1/2)^3

v=4/3*22/7*1/8

v=11/21

v=0.52 units^3

4 0

2 years ago

Prove that the difference between a two-digit number and the product of its digits will always be a 2 digit number.

slamgirl [31]

Step-by-step explanation:

Let the two-digit number is $xy$

<u>This can be written as:</u>

10x + y, where 1 ≤ x ≤ 9 and 0 ≤ y ≤ 9

<u>The difference between the number and product of its digits is:</u>

d = 10x + y - xy

<u>Rewrite this as below:</u>

d = 10x - xy + y - 10 + 10 =

x(10 - y) - (10 - y) + 10 =

(x - 1)(10 - y) + 10

<u>We see that:</u>

0 ≤ x - 1 ≤ 8 according to the condition given above
1 ≤ 10 - y ≤ 10 again according to the condition given above

<u>The value of d is then:</u>

0 + 10 ≤ d ≤ 8*10 + 10
10 ≤ d ≤ 90

<h3>Proved</h3>

7 0

2 years ago

Read 2 more answers

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago

The formula m = 12,000 + 12,000rt 12t gives Keri's monthly loan payment, where r is the annual interest rate and t is the length

alexandr1967 [171]

Answer:

$240

Step-by-step explanation:

Fill in the given numbers and do the arithmetic.

$m=\dfrac{12,000+12,000rt}{12t}=\dfrac{12,000+12,000\cdot 0.04\cdot 5}{12\cdot 5}\\\\m=\dfrac{14,400}{60}=240$

Keri's monthly loan payment is $240 per month.

3 0

3 years ago

Read 2 more answers