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3 years ago

Carla bought a T-shirt for $17.65 and a sweater for $31.79.

Mathematics

1 answer:

goldfiish [28.3K]3 years ago

4 0

Just add them together
$17.65 + $31.79 = $49.44

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A manufacturer of a certain brand of appliance estimates that he can sell 5000 units a year at Php 900.00 each and that he can s

Radda [10]

First solve the return in each price per unit

Return = number units sold x price per unit

Return1 = 5000 units x Php 900

Return1 = php 4,500,000

Next is solve the other price per unit

Return2 = number units sold x price per unit

Return2 = (5000 + 1500 units0 x ( php 900 – 100)

Return2 = php 5,200,000

So the php 800 per unit will have greater return

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Find the sum of the series Summation from n equals 1 to infinity (StartFraction 3 Over StartRoot n plus 2 EndRoot EndFraction mi

Marizza181 [45]

Looks like the series is supposed to be

$\displaystyle\sum_{n=1}^\infty\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}$

The series telescopes; consider the $k$ th partial sum of the series,

$S_k=\displaystyle\sum_{n=1}^k\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}$

$S_k=\displaystyle\left(\frac3{\sqrt3}-\frac32\right)+\left(\frac32-\frac3{\sqrt5}\right)+\cdots+\left(\frac3{\sqrt{k+1}}-\frac3{\sqrt{k+2}}\right)+\left(\frac3{\sqrt{k+2}}-\frac3{\sqrt{k+3}}\right)$

$\implies S_k=\dfrac3{\sqrt3}-\dfrac3{\sqrt{k+3}}$

As $k\to\infty$ , the second term converges to 0, leaving us with

$\displaystyle\sum_{n=1}^\infty\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}=\frac3{\sqrt3}=\boxed{\sqrt3}}$

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3 years ago

Please complete the table.

FromTheMoon [43]

Answer:

my answer in this picture.......

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Brainliest + Points! Mathematicians needed please

oksano4ka [1.4K]

Answer:

the correct answer is C). 3,600

Step-by-step explanation:

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Two circles of radius 1 are centered at $(4,0)$ and $(-4,0).$ How many circles are tangent to both of the given circles and also

galben [10]

Answer:

1 circle

Step-by-step explanation:

Given two circles (red circles on the diagram).

There are two tangent circles to both of the given circles (blue circles on the diagram), and only one of them is passing through the point (0,5).

Let's check it.

The equations of the tangent circles are

$x^2+y^2=9\ [\text{Smaller tangent circle}]\\ \\x^2+y^2=25\ [\text{Larger tangent circle}]$

Check whether point (0,5) lies on the smaller circle:

$0^2 +5^2 =0+25=25\neq 9$

Check whether point (0,5) lies on the larger circle:

$0^2 +5^2 =0+25=25$

Yes

<u>Answer: </u>1 circle

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3 years ago