Answer:I need the answer too if u got it let me know please!
Step-by-step explanation:
Answer:
21.6 liters
Step-by-step explanation:
40 drops make up a volume of 10 mL
Therefore, the volume of 1 drop of water = 10mL/40 = 1/4 mL= 0.25mL
Since the tap loses 1 drop of water in 1 sec, it loses 0.25mL of water in 1 second
60 seconds make up 1 second so volume of water lost in 1 minute = 0.25 x 60 = 15 mL
60 minutes make up 1 hour so volume of water lost in 1 hour = 15 x 60 = 900 mL
24 hours make up a day so volume of water lost in 1 day = 900 x 24 = 21,600 mL
Since 1000 mL make up 1 liter, divide by 1000 to get volume in liters
Volume of water lost in 1 day = 21600/1000 = 21.6 liters
Can be done as one equation
V lost in one day = 0.25 x 3600 x 24 mL = 21600 mL = 21.6 L
Answer:
3+g=- 134
Step-by-step explanation:
Answer:
0.1587
Step-by-step explanation:
Let X be the commuting time for the student. We know that 
. Then, the normal probability density function for the random variable X is given by
![f(x) = \frac{1}{\sqrt{2\pi(5)^{2}}}\exp[-\frac{(x-\mu)^{2}}{2(5)^{2}}]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%7B2%5Cpi%285%29%5E%7B2%7D%7D%7D%5Cexp%5B-%5Cfrac%7B%28x-%5Cmu%29%5E%7B2%7D%7D%7B2%285%29%5E%7B2%7D%7D%5D)
. We are seeking the probability P(X>35) because the student leaves home at 8:25 A.M., we want to know the probability that the student will arrive at the college campus later than 9 A.M. and between 8:25 A.M. and 9 A.M. there are 35 minutes of difference. So,
= 0.1587
To find this probability you can use either a table from a book or a programming language. We have used the R statistical programming language an the instruction pnorm(35, mean = 30, sd = 5, lower.tail = F)
your answer is a ok i hope this helpful
