Question

What is the range of the function f(x)= square root of x-8+6

Answer 1

Answer:

• The range of the given function is  [6, + ∞)

Step-by-step explanation:

It is assumed the function is:

• $f(x)=\sqrt{x-8} +6$

We know the square root is non-negative, so:

• x - 8 ≥ 0  therefore the function gets values

• f(x) ≥ 0 + 6
• f(x) ≥ 6

We can show this as:

• f(x) ∈ [6, + ∞)