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gavmur [86]
2 years ago
13

What is the range of the function f(x)= square root of x-8+6

Mathematics
1 answer:
Shtirlitz [24]2 years ago
8 0

Answer:

  • The range of the given function is  [6, + ∞)

Step-by-step explanation:

It is assumed the function is:

  • f(x)=\sqrt{x-8} +6

We know the square root is non-negative, so:

  • x - 8 ≥ 0  therefore the function gets values

  • f(x) ≥ 0 + 6
  • f(x) ≥ 6

We can show this as:

  • f(x) ∈ [6, + ∞)
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