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3 years ago

Find the value of x!!!!!!

Mathematics

2 answers:

Y_Kistochka [10]3 years ago

7 0

Answer:

63 degrees

Step-by-step explanation:

All angles of a triangle always add up to 180 degrees.

So you take both angles and add them together-55+72=117

You then would take 180 and subtract the total- 180-117=63

And that would be your final answer

nevsk [136]3 years ago

5 0

Answer:

Sum of 3 angles in a triangle=180

x+55+72= 180

x+ 127=180

x= 180-127

x= 53

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3 years ago

Justin weighs 15 pounds less than Greg weighs. Half of Greg's weight is 75 pounds less than Justin's weight. How much does each

solniwko [45]

Answer:

justin = 135 & greg = 150

Step-by-step explanation:

equations:

(justin is 15lbs under greg) j-15=g

(find gregs full weight by doubling bc the problem gave you half) 75*2=150

(plug in gregs wieght to find justins weight) j-15=150 -> j=135

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3 years ago

Dubnium-262 has a half-life of 34 s. How long will it take for 500.0 grams to

dmitriy555 [2]

Answer:

the time taken for the radioactive element to decay to 1 g is 304.8 s.

Step-by-step explanation:

Given;

half-life of the given Dubnium = 34 s

initial mass of the given Dubnium, m₀ = 500 grams

final mass of the element, mf = 1 g

The time taken for the radioactive element to decay to its final mass is calculated as follows;

$1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} = (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500}) = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s$

Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.

4 0

3 years ago

Which statement best describes the domain of the function represented in the graph?

MissTica

the answer is choice number 3

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3 years ago

Read 2 more answers

the midpoint of kl is m(4.8, -7.8). one endpoint is l(0.6, -5.6). find the coordinates of the other endpoint k.

Vera_Pavlovna [14]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&k&(~ x &,& y~) 
% (c,d)
&l&(~ 0.6 &,& -5.6~)
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}\quad ,\quad \cfrac{ y_2 + y_1}{2} \right)$

$\bf \left( \cfrac{0.6+x}{2}~~,~~\cfrac{-5.6+y}{2} \right)~=~\stackrel{midpoint}{(4.8~,~-7.8)}\quad 
\begin{cases}
\cfrac{0.6+x}{2}=4.8\\\\
0.6+x=9.6\\
\boxed{x=9}\\
---------\\
\cfrac{-5.6+y}{2}=-7.8\\\\
-5.6+y=-15.6\\
\boxed{y=10}
\end{cases}$

8 0

3 years ago