Help please .............................

Mathematics

1 answer:

Rufina [12.5K]2 years ago

7 0

Answer:I think its the second one

Step-by-step explanation:

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5, 3, 2, 6, 7, 9, 1, 15, 4, 2, 3, 3, 9, 5, 1, ?

Shkiper50 [21]

Answer:

I have no idea thank you for the points

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

A batch consists of 12 defective coils and 88 good ones. Find the probability of getting two good coils when two coils are rando

Allushta [10]

<u>Answer:</u>

The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744

<u>Solution:</u>

Total number of coils = number of good coils + defective coils = 88 + 12 = 100

p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) $\times$ p(getting 2 good coils for second selection)

p(first selection) = p(second selection) = $\frac{\text { number of good coils }}{\text { total number of coils }}$

Hence, p(getting 2 good coil for two selection) = $\frac{88}{100} \times \frac{88}{100} =\bold{0.7744}$

5 0

3 years ago

Which equation has the same soultions as x^2+6×-7=0

blagie [28]

$x^2+6x-7=0 \\ a=1 \\ b= 6 \\ c=-7 \\ \\ \boxed{\boxed{\Delta=b^2-4ac}} \\ \\ \Delta=6^2-4*1*(-7) \\ \Delta=36-(-28) \\ \Delta=64 \\ \Delta\ \textgreater \ 0 \Rightarrow \text{we have 2 solutions :} X_1 \ and X_2 \\ \\ \boxed{X_1= \frac{-b- \sqrt{\Delta} }{2a} } \Rightarrow X_1= \frac{-6-8}{2}=-7 \\ \\ \boxed{X_2= \frac{-b+ \sqrt{\Delta} }{2a} } \Rightarrow X_2= \frac{-6+8}{2} =1$