The correct answer is:
A line that crosses segment at right angles while dividing the segment in half is called <u>a perpendicular bisector</u>
Step-by-step explanation:
A bisector is a line that divides a line segment in two equal parts. A perpendicular bisector is a line that is perpendicular to given line segment and passes through the mid-point of the line segment. It can also be said as that the line perpendicular to a line segment that divides the lines in half is called the perpendicular bisector.
The correct answer is:
A line that crosses segment at right angles while dividing the segment in half is called <u>a perpendicular bisector</u>
Keywords: Perpendicular, bisector
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Answer:
See explaination
Step-by-step explanation:
B. The equality relation on the real numbers is an equivalence relation.
This statement is true
C. If RR is a reflexive relation on a set S, then any two RR- related elements of S must also be R2R2 related.
This statement is true
F. The less than or equal relation on the real numbers fails to be an equivalence relation because it is reflexive and transitive but not symmetric
This statement is true
H. If RR is an equivalence relation, then R2
This statement is true
Answer:
f−1(x)=√x+123,−√x+123
Step-by-step explanation:
Answer:
V = 141.37 cm³
Surface area = 150.80 cm²
i. Doubling the radius to 6 cm, while the height remains 5
Step-by-step explanation:
Given that :
Radius, r = 3cm
Height, h = 5cm
Volume , V of right cylinder :
V = πr²h
V = π * 3² * 5
V = 141.37166
V = 141.37 cm³
Surface Area :
2πr(h + r)
2 * π * 3(3 +5)
18.849555(8)
150.79644
= 150.80 cm²
Volume at r = 6 ; h = 5
V = π * 6² * 5
V = 565.48667 cm³
Volume at r = 3 ; h = 15
V = π * 3² * 15
V = 424.11500 cm³
To increase volume,
We can use the substitution method to solve this problem.
The second equation is

, so we can plug in 2x for 'y' in the first equation:


Multiply:

Combine like terms:

This is the x-value of our solution, we can plug this into any of the two equations to find the y-value:


Multiply:

This is the y-value of our solution. So our entire solution is (3, 6).