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Xelga [282]
2 years ago
14

The amount a gardener gets paid is directly proportional to the number of hours it takes for him to complete the job.

Mathematics
1 answer:
astraxan [27]2 years ago
8 0

Answer:

  £105

Step-by-step explanation:

The pay is proportional to the time, so working 18/12 = 3/2 times as long will gain the gardener 3/2 times the pay:

  3/2 × £70 = £105

He would get paid £105 for an 18-hour job.

__

Here are a couple of other solution methods.

<h3>as a proportion</h3>

  pay/hours = ?/(18 hours) = £70/(12 hours)

Multiplying by 18 hours, we get ...

  ? = £70×(18 hours)/(12 hours) = £70×(18/12)

  ? = £105 . . . . pay for 18 hours

He would get paid £105 for 18 hours.

__

<h3>as direct proportion equation</h3>

The equation for a directly proportional relationship is ...

  y = kx

If we let y represent pay and x represent hours, then we have ...

  70 = k(12)   ⇒   k = 70/12 = 35/6

Then for 18 hours, the pay is ...

  y = (35/6)x

  y = (35/6)(18) = 35(3) = 105

He would get paid £105 for 18 hours.

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Answer:

(m+p,n+r)

Step-by-step explanation:

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M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Substitute the coordinates to get;

M=(\frac{2m+2p}{2},\frac{2n+2r}{2})

M=(\frac{2(m+p)}{2},\frac{2(n+r)}{2})

M=(m+p,n+r)

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klio [65]

Answer:

10.2 cm²

Step-by-step explanation:

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HELP! I am confused since the -5 was added, so would it be the slope or would -7 be the slope?
In-s [12.5K]

Answer:

slope = 35; y-intercept = -45

Step-by-step explanation:

Function f(x) is written in the slope-intercept form, y = mx + b.

f(x) = -7x + 9

You compare it with

f(x) = mx + b, and you see that m, the slope, is -7, and b, the y-intercept is 9.

Now we deal with function h(x).

h(x) = -5(-7x + 9)

This is not written in the y = mx + b form, but we can put it in that form by distributing the -5.

h(x) = 35x - 45

Now, h(x) is written in the y = mx + b form. We see clearly that m = 35, so the slope of function h is 35. We also see that b, the y-intercept is -45.

Answer: slope = 35; y-intercept = -45

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 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
vodka [1.7K]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

To find:

The values of \sin 2x, \cos 2x, \tan 2x.

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

\sin^2 x+\cos^2 x=1

(-\dfrac{15}{17})^2+\cos^2 x=1

\cos^2 x=1-\dfrac{225}{289}

\cos x=\pm\sqrt{\dfrac{289-225}{289}}

x lies in the III quadrant. So,

\cos x=-\sqrt{\dfrac{64}{289}}

\cos x=-\dfrac{8}{17}

Now,

\sin 2x=2\sin x\cos x

\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})

\sin 2x=-\dfrac{240}{289}

And,

\cos 2x=1-2\sin^2x

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\cos 2x=1-2(\dfrac{225}{289})

\cos 2x=\dfrac{289-450}{289}

\cos 2x=-\dfrac{161}{289}

We know that,

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

\tan 2x=\dfrac{240}{161}

Therefore, the required values are \sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}.

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What is the sum of the probability of drawing a green marble and the probability of not drawing a green marble?
andrey2020 [161]

Yo sup??

the answer is 1 because

P(E)+P(E')=1

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