Given triangle ABC with coordinates A(−6, 4), B(−6, 1), and C(−8, 0), and its image A′B′C′ with A′(−2, 0), B′(−5, 0), and C′(−6,
Zinaida [17]
Answer:
The line of reflection is at y = x+6.
Step-by-step explanation:
The perpendicular bisector of AA' is a line with slope 1 through the midpoint of AA', which is (-4, 2). In point-slope form, the equation is ...
y = 1(x +4) +2
y = x + 6 . . . . . . . line of reflection
Answer:
Population after 4 years = 49 (nearest unit)
Population after 5 years = 47 (nearest unit)
Step-by-step explanation:
Yearly decrease = 4.6%
Decrease factor (what's left) = (100-4.6)% = 0.954
Current population, P = 60
population after n years = P(0.954)^n (to the nearest unit)
Population after 4 years = 60(0.954)^4 = 49.7 = 49 (nearest unit)
Population after 5 years = 60(0.954)^5 = 47.4 = 47 (nearest unit)
Usando la distribución binomial, hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.
<h3>¿Qué es la distribución binomial?</h3>


Los parámetros son:
- n es el número de ensayos.
- p es la probabilidad de éxito en un ensayo
En este problema, hay que:
- 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal, o sea p = 0.2.
- Llegan 10 empleados, o sea, n = 10.
La probabilidad de que el guardia de seguridad encuentre al menos uno en la base militar restringida es dada por:

En que:


Por eso:

Hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.
Puede-se aprender más a cerca de la distribución binomial en brainly.com/question/25132113
Answer:
70 + 4D
Step-by-step explanation:
- (2 x 100) + (7 x 10) + (4 x D) + (2 x 100)
- (200) + (70) + 4D + 200
-200 + 70 +4D + 200
-130 + 4D + 200
70 + 4D
<u>Answer:</u>
Cost of sand = £150
Cost of bricks = £157.5
Cost of cement = £134
Total cost = £441.50
<u>Step-by-step explanation:</u>
We are given that:
2 tonnes of sand is for £75.00 per tonne,
20 bags of cement are for £6.70 per bag,
350 bricks at 45p each,
So, 2 tonnes of sand at £75.00 per tonne = 2 * £75.00 = £150.00
20 bags of cement at £6.70 per bag = 20 * £6.70 = £134.00
350 bricks at 45p each = 350 * £0.45 = £157.50
Therefore, the total cost of all the materials = £150 + £134 + £157.5 = £441.50