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Phoenix [80]
2 years ago
7

What is 14r-13s+19r+13s-18

Mathematics
1 answer:
Zielflug [23.3K]2 years ago
8 0
77 is ur answer hope this helps u
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What are the values of the trigonometric ratios for this triangle?
nika2105 [10]

Answer:

sin = o/h = 5/13

cos = a/h = 12/13

tan = o/a = 5/12

o - opposite

a- adjacent

h - hypotenuse

6 0
2 years ago
 Hester sells televisions. She earns a fixed amount for each television and an additional $ 15 if the buyer gets an extended war
tiny-mole [99]

Answer:

y =mx +bx

Where y is the total amount earned, m the amount for each extended warranty and b the fixed cost and x the total amount of TVs

For this case the value of x = 16 since we have 16 Tvs with extended warranties and we can do this:

1200 = 15*16 +16b

and solving for b we got:

b= \frac{1200-15*16}{16}= 60

And then we can conclude that she earns 60 for each TV

Step-by-step explanation:

For this case we can set a linear model like this:

y =mx +bx

Where y is the total amount earned, m the amount for each extended warranty and b the fixed cost and x the total amount of TVs

For this case the value of x = 16 since we have 16 Tvs with extended warranties and we can do this:

1200 = 15*16 +16b

and solving for b we got:

b= \frac{1200-15*16}{16}= 60

And then we can conclude that she earns 60 for each TV

8 0
3 years ago
PLS HELP ME ASAP I AM TIMED explain ur asnwer DONT GUESS THATS REALLY IMMATURE AND RUDE
Sav [38]
The answer is D

See attached picture:

8 0
2 years ago
he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s
sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

P(X

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) =[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

NORMSDIST(6.366)-NORMSDIST(-1.47)

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0
2 years ago
If line BA is a midsegment of triangle XYZ, find x.
DIA [1.3K]
For midsegment theorem
And parallels lune are twice

So AB = YZ /2

AB = 10/2 =5

BUT AB = X–1 =5

X–1 = 5 = X = 1+5 =6

X =;6


..

MARK AS Brainliest
6 0
3 years ago
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