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3 years ago

14

Solve for x. X/3=5/8 1 7/8 4 4/5 8/15

1 answer:

polet [3.4K]3 years ago

3 0

Answer:

option A i. e. the first option is the correct option.

Step-by-step explanation:

$\frac{x}{3} = \frac{5}{8}$

$x = \frac{15}{8} = 1 \frac{7}{8}$

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(-2/3)^7*(3/5)^6*(5/6)^5*(1/3)^-7 simplify of law of indices

Wewaii [24]

Answer:

$\boxed {-\frac{12}{5}}$

Step-by-step explanation:

Solve the following expression:

$(-\frac{2}{3})^{7} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

-Calculate $-\frac{2}{3}$ to the power of $7$ :

$(-\frac{2}{3})^{7} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

$-\frac{128}{2187} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

-Calculate $\frac{3}{5}$ to the power of $6$ :

$-\frac{128}{2187} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

$-\frac{128}{2187} \times (\frac{729}{15625}) \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

-Multiply both $-\frac{128}{2187}$ and $\frac{729}{15625}$ :

$-\frac{128}{2187} \times (\frac{729}{15625}) \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

$-\frac{128}{46875} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

-Calculate $\frac{5}{6}$ to the power of $5$ :

$-\frac{128}{46875} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

$-\frac{128}{46875} \times (\frac{3125}{7776}) \times (\frac{1}{3})^{-7}$

-Multiply both $-\frac{128}{46875}$ and $\frac{3125}{7776}$ :

$-\frac{128}{46875} \times (\frac{3125}{7776}) \times (\frac{1}{3})^{-7}$

$-\frac{4}{3645} \times (\frac{1}{3})^{-7}$

-Calculate $\frac{1}{3}$ to the power of $-7$ :

$-\frac{4}{3645} \times (\frac{1}{3})^{-7}$

$-\frac{4}{3645} \times 2181$

-Multiply both the $-\frac{4}{3645}$ and $2187$ :

$-\frac{4}{3645} \times 2181$

$\boxed {-\frac{12}{5}}$

Therefore, the final answer is $-\frac{12}{5}$ .

3 0

3 years ago

. Gerald wants to borrow $12,000 in order to buy an engagement ring. He wants to repay the loan by making monthly installments f

garri49 [273]

Answer:

$550.97

Step-by-step explanation:

The amortization formula will tell you the payment amount.

A = P(r/12)/(1 -(1 +r/12)^(-12t))

where A is the monthly payment, P is the principal amount of the loan, r is the annual interest rate, t is the number of years. Using your values, this is ...

A = $12,000(0.095/12)/(1 -(1 +0.095/12)^(-12·2)) ≈ $550.97

The amount of Gerald's payment is $550.97.

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3 years ago

How to write ten and twenty-four hundredths

DENIUS [597]

The answer to this is 10.24

8 0

3 years ago

Enter the number in standard notation.<br> 7x 102=<br> PLEASE HELP FAST

kiruha [24]

Answer:714

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A fourth degree polynomial with real coefficients can have -4, 8i,+4i, and as its zeros. True or false? Justify your answer.

liraira [26]

You didn't give the fourth zero, but the answer is still false. If you have a root or an imaginary number as a zero, then its conjugate is also a zero. So if 8i is a zero, then -8i must also be a zero, and if 4i is a zero, then -4i must be a zero, with those zeros and -4, the number of zeroes exceeds the number of zeroes that a fourth degree polynomial can have.

4 0

3 years ago