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agasfer [191]
2 years ago
5

Y>-3x +3 y≥ 2x-2 O (1,0) O (-1,1) O(2,2) (0,3)

Mathematics
1 answer:
Ainat [17]2 years ago
3 0

Answer:

(1,0)

Step-by-step explanation:

y>-3x +3

y≥ 2x-2

If we plot these two inequalities, we can see where the lines intersect,  See attached graph.

They intersect at (1,0)

We can also do this mathematically:

  y>-3x +3

<u>- (y≥ 2x-2)</u>

0 \geq -5x + 5

5x \geq 5

x \geq 1

If x = 1:

y≥ 2x-2

y≥ 2(1)-2

y≥ 0

(x,y) = (1,0)

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Leno4ka [110]

sorry buddy have no idea

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3 years ago
David is 4 times older than Adan. Adan is 2 times older than julio. Julio is 12, how old is David?
dem82 [27]
12 x 2 = 24 (Julio), 24 x 4 = 96 (David).
3 0
4 years ago
Read 2 more answers
Starting with x1 = 2, find the third approximation x3 to the root of the equation x3 − 2x − 2 = 0.
andrew11 [14]

Answer:

0.8989

Step-by-step explanation:

Using the Newton's Raphson approximation formula.

Xn+1 = Xn - f(Xn)/f'(Xn)

Given f(x) = x³-2x+2

f'(x) = 3x²-2

If the initial value X1 = 2

X2 = X1 - f(X1)/f'(X1)

X2 = 2 - f(2)/f'(2)

f(2) = 2³-2(2)+2

f(2) = 8-4+2

f(2) = 6

f'(2) = 3(2)²-2

f'(2) = 10

X2 = 2- 6/10

X2 = 14/10

X2 = 1.4

X3 = X2 - f(X2)/f'(X2)

X3 = 1.4 - f(1.4)/f'(1.4)

f(1.4) = 1.4³-2(1.4)+2

f(1.4) = 2.744-2.8+2

f(1.4) = 1.944

f'(1.4) = 3(1.4)²-2

f'(1.4) = 3.880

X3 = 1.4- 1.944/3.880

X3 = 1.4 - 0.5010

X3 = 0.8989

Hence the value of X3 is 0.8989

6 0
3 years ago
Please help me out with this!!<br> BRAINLIEST AVAILABLE!!
lapo4ka [179]

Answer:

xy = 1

k = 79

Step-by-step explanation:

Question One

The first and third frames look to me to be the same. I'll treat them that way.

y = x^2                        Equate y = x^2 to the result of 2y + 6 = 2x + 6

2y + 6 = 2(x + 3)         Remove the brackets

2y + 6 = 2x + 6           Subtract 6 from both sides

2y = 2x                       Divide by 2

y = x

Now solve these two equations.

so x^2 = x                  

x > 0

1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is

x(x) = x                           Divide both sides by x            

x = 1                            

y = x^2                           Put x = 1 into x^2

y = 1^2                           Solve

y = 1                      

The second solution is

(1,1)

xy = 1*1

xy = 1

Answer: A

Question Two

square root(k + 2) - x = 0

Subtract x from both sides

sqrt(k + 2) = x                Square both sides

k + 2 = x^2                    Let x = 9

k + 2 = 9^2                    Square 9

k + 2 = 81

k = 81 - 2

k = 79

4 0
3 years ago
I need help with this one pls!
Alex73 [517]

Hi there!

\large\boxed{b = \frac{a}{ac - 1}}

We can begin by making each fraction have a common denominator:

If we make each have a common denominator of ab, we get:

\frac{b}{ab} + \frac{a}{ab} = c

Simplify:

\frac{a + b}{ab}  = c

Multiply both sides by ab:

a + b = cab

Move b to the opposite side:

a = cab - b

Factor out b:

a = b(ac - 1)

Divide by (ac - 1):

\frac{a}{ac - 1} = b

4 0
3 years ago
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