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3 years ago

A number that tells how many times the base is used as a factor

Mathematics

1 answer:

forsale [732]3 years ago

4 0

An exponent is a number that tells how many times the base is used as a factor.

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What equation, in point-slope form, matches the graphed line shown? Question 3 options: y−5=−23(x+9) y−2=−34(x−6) y+6=45(x+3) y−

ziro4ka [17]

Step-by-step explanation:

the line passes through (6, 2) and (10, -1),

the slope =

(-1-2)/(10-6) = -3/4

the equation :

y-2 = -3/4(x -6)

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3 years ago

I need help with this question it’s due today please help.

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3 years ago

Express 29,000 as a fraction

AleksandrR [38]

Answer:

29000/1

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3 years ago

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One car travels 58mph and another at 52mph when will they be 363 miles apart

frosja888 [35]

You would need the departure time of each vehicle to know exactly when they would be 363 miles apart from each other so there is no way to tell when they would be 363 miles apart

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3 years ago

urn I contains 1 red chip and 2 white chips; urn II contains 2 red chipsand 1 white chip. One chip is drawn at random from urn I

vitfil [10]

Answer:

Following are the answer to this question:

Step-by-step explanation:

In the question first calls the W if the transmitted chip was white so, the W' transmitted the chip is red or R if the red chip is picked by the urn II.

whenever a red chip is chosen from urn II, then the probability to transmitters the chip in white is:

$P(\frac{w}{R}) = \frac{P(W\cap R)}{P(R)} \ \ \ \ \ _{Where}\\\\P(R) = P(W\cap R) + P(W'\cap R) \\$

The probability that only the transmitted chip is white is therefore $P(W) = \frac{2}{3}\\$ , since urn, I comprise 3 chips and 2 chips are white.

But if the chip is white so, it is possible that urn II has 4 chips and 2 of them will be red since urn II and 2 are now visible, and it is possible to be: $P(\frac{R}{W}) = \frac{2}{3}$

$P(W\cap R) = P(W) \times P(\frac{R}{W}) \\$

$= \frac{2}{3}\times \frac{2}{4} \\\\= \frac{2}{3}\times \frac{1}{2} \\\\= \frac{2}{3}\times \frac{1}{1} \\\\=\frac{1}{3}\\\\= 0.333$

Likewise, the chip transmitted is presumably red $(P(W')= \frac{1}{3})$ and the chip transferred is a red chip of urn II $(P(\frac{R}{W'})= \frac{3}{4}$ , and a red chip is likely to be red $(\frac{R}{W'})$ .

Finally, $P(W'\cap R) = P(W') \times P(\frac{R}{W'})\\$

$= \frac{1}{3} \times \frac{3}{4} \\\\ = \frac{1}{1} \times \frac{1}{4} \\\\=\frac{1}{4}\\\\= 0.25$

The estimation of $P(R)$ and $P(\frac{W }{R})$ as:

$P(R) = 0.3333 + 0.25\\\\ \ \ \ \ \ \ \ \ \ = 0.5833 \\\\ P(\frac{W}{R}) = \frac{0.3333}{0.5833} \\\\\ \ \ \ \ \ \ = 0.5714$

4 0

3 years ago