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Hatshy [7]
3 years ago
5

Frank has baseball practice every 4th day and choir practice every 6th day. When will he have base baseball and choir practice o

n the same day?
Mathematics
2 answers:
Firdavs [7]3 years ago
8 0
He will have basketball and choir on the 12th day
Murljashka [212]3 years ago
6 0
12th day because the least common multiple of 4 and 6 is 12
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Does the order in which you add two integers with the same sign affect the sum
kondor19780726 [428]
If you add positive 5 and positive 5, you'll get positive 10.
If you add positive 5 and negative 5, you'll get positive 0.
If you add negative 5 and negative 5, you'll get negative 10.

-5 + 5 = -5 + 5
5 + 5 = 5 + 5
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Does that help your question?
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3 years ago
How many pennies are in one-dollar??
OleMash [197]

Answer:

There are 100 pennies in one dollar.

Step-by-step explanation:

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3 years ago
Please help me on math homework! <br> File attached! :D
r-ruslan [8.4K]
Use pythagorena theorme

D=\sqrt{(x1-x2)^{2}+(y1-y2)^{2}}
NOTE: x1 and x2 means the first x and second x, not x^1 and x^2

points given are
(1,1)
(5,6)
x1=1
y1=1
x2=5
y2=6
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6.403


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7 0
3 years ago
Read 2 more answers
The mean preparation fee H&amp;R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t
astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)=\frac{ME*\sqrt{N}}{s } where

  • Me is the margin of error from the mean
  • s is the standard deviation of the population
  • N is the sample size

a.

z(p)=\frac{8*\sqrt{30}}{50 } ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

b.

z(p)=\frac{8*\sqrt{50}}{50 } ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

c.

z(p)=\frac{8*\sqrt{100}}{50 } ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

d.

Minimum required sample size for 0.95 probability is

N≥(\frac{z*s}{ME} )^2 where

  • N is the sample size
  • z is the corresponding z-score in 95% probability (1.96)
  • s is the standard deviation (50)
  • ME is the margin of error (8)

then N≥(\frac{1.96*50}{8} )^2 ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

7 0
3 years ago
Megan earns $20.00 by walking dogs. She uses all of her earnings to buy a shirt for $12.85 and some stickers for $0.65 each. How
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The answer is B: 11.

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