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aleksley [76]
3 years ago
7

Explain why the graph of

k+1" alt="y=2x^{2} +4x-k+1" align="absmiddle" class="latex-formula"> has no x-intercepts when k=-5
Mathematics
1 answer:
Oksana_A [137]3 years ago
3 0
Since the equation then turns into y=2x^2+4x+5+1, the +5+1 moves the vertex higher up on the y axis, meaning there would be no x-intercepts
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Write an equation of the line with the given slope and containing the given point write the equation in the slope intercept form
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4 0
3 years ago
How do i solve this?
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7 0
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A regular pyramid has a regular polygon base and a __over the center of the base
Rufina [12.5K]

Answer: Vertex

Step-by-step explanation:

To solve this exercise you must keep on mind the definitions shown below:

1. By definition, a regular pyramid is a right pyramid whose base is a regular polygon.

2. By definition, a regular polygon is a polygon whose sides have equal lenghts.

3. By definition the apex (which is the vertex at the tip of the pyramid) of a right pyramid lies directly above the center of the base.

Therefore, keeping the above on mind, you can conclude that:

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4 0
3 years ago
Do anyone know how to solve this? need the answer fast.
Nikitich [7]
The value of g^-1(-3) is the value of x that makes g(x) = -3. To find it, we can solve
.. (x +4)/(2x -5) = -3
.. x +4 = -3(2x -5)
.. 7x = 11
.. x = 11/7

The desired value is
.. (3/11)*g^-1(-3)
.. = (3/11)*(11/7)
.. = 3/7

\frac{3}{11} g^{-1}(-3) = \frac{3}{7}
6 0
3 years ago
I urgently need help!!!!
LekaFEV [45]

Answer:

A. C (3,5)

Step-by-step explanation:

This makes the most sense because of the position point C is at on the coordinate plane. It is above point D, which has a x-axis of 3. Option A is the only one that has an x-axis of 3.

Hope it helps!

6 0
3 years ago
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