Easiest ways to solve them are to take the denominator and numerator and and divide the one you are asked to use to answer and divide and see if it works on both.
Example: first 105 / 15 = 7 ) Then: 105 / 7 = 15
119 ) 119 / 7 = 17
Hope I helped. :D
Answer:
<h3>X<5 and X<3</h3>
Step-by-step explanation:
To solve this problem, first, you have to isolate it on one side of the equation. Remember to solve this problem, isolate x on one side of the equation.
x+3<8 and 3(x+4)-11<10
x+3<8
x+3-3<8-3 (First, subtract 3 from both sides.)
8-3 (Solve.)
8-3=5
x<5
3(x+4)-11<10
3(x+4)-11+11<10+11 (Add 11 from both sides.)
10+11 (Solve.)
10+11=21
3(x+4)<21
3(x+4)/3<21/3 (Next, divide by 3 from both sides.)
21/3 (Solve.)
21/3=7
x+4<7
x+4-4<7-4 (Then, subtract 4 from both sides.)
7-4=3
x<3
The correct answer is x<5 and x<3.
<em><u>
</u></em>
<h2>284 .67 square yards </h2>
<em><u>Given</u></em>
- <em><u>Length</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>3</u></em><em><u>0</u></em><em><u>½</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>6</u></em><em><u>1</u></em><em><u>/</u></em><em><u>2</u></em>
- <em><u>Bredth</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>9</u></em><em><u>⅓</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>2</u></em><em><u>8</u></em><em><u>/</u></em><em><u>3</u></em>
<em><u>To </u></em><em><u>find</u></em><em><u>:</u></em>
- <em><u>The </u></em><em><u>area </u></em><em><u>covered</u></em><em><u> </u></em><em><u>by </u></em><em><u>the </u></em><em><u>tent.</u></em>
<em><u>Solution</u></em><em><u> </u></em>
- <em><u>Multiplying</u></em><em><u> </u></em><em><u>The </u></em><em><u>Given</u></em><em><u> </u></em><em><u>Length</u></em><em><u> </u></em><em><u>by </u></em><em><u>the </u></em><em><u>given</u></em><em><u> </u></em><em><u>Bredth</u></em><em><u> </u></em><em><u>since </u></em><em><u>the </u></em><em><u>area </u></em><em><u>of </u></em><em><u>a </u></em><em><u>rectangle</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>LB</u></em>
- <em><u>6</u></em><em><u>1</u></em><em><u>/</u></em><em><u>2</u></em><em><u>× </u></em><em><u>2</u></em><em><u>8</u></em><em><u>/</u></em><em><u>3</u></em>
- <em><u>=</u></em><em><u> </u></em><em><u>2</u></em><em><u>8</u></em><em><u>4</u></em><em><u> </u></em><em><u>.</u></em><em><u>6</u></em><em><u>7</u></em><em><u> </u></em><em><u>square</u></em><em><u> </u></em><em><u>yards.</u></em>
<em><u>Hope </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em>
<em><u>~ʆᵒŕ∂ཇꜱꜹⱽẻⱮë</u></em>
Discount %= 10%
Discount= x × 10%= x/10
Price after discount =x-(x/10)= 9x/10
But, given price after discount = rs 450
9x/10=450
9x=4500
x=4500/9= rs 500
Now, if the roots are -2 and 3, that simply means

now, as far as the leading term's coefficient having a 3, we can simply make it a "common factor" of both terms.