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aleksley [76]
3 years ago
7

Explain why the graph of

k+1" alt="y=2x^{2} +4x-k+1" align="absmiddle" class="latex-formula"> has no x-intercepts when k=-5
Mathematics
1 answer:
Oksana_A [137]3 years ago
3 0
Since the equation then turns into y=2x^2+4x+5+1, the +5+1 moves the vertex higher up on the y axis, meaning there would be no x-intercepts
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77julia77 [94]

Answer:

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3 0
3 years ago
WILL GIVE BRAINLIEST& 15 PTS.
kicyunya [14]

Answer:

The given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

Step-by-step explanation:

Consider the given fraction \frac{x^3-x^2}{x^3}

We have to reduce the fraction to the lowest terms.

Consider numerator x^3-x^2

We can take x² common from both the term,

Thus, numerator can be written as x^2(x-1)

Given expression can be rewritten as ,

\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}

We can now cancel x^2 from both numerator and denominator,

\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}

\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}

Thus, the given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

6 0
3 years ago
Read 2 more answers
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