The target temperature for a laboratory is 72° Fahrenheit. It
1 answer:
The inequality |t - 72| ≤ 2 represents the target temperature for a laboratory is 72° Fahrenheit, and it can vary by up to 2° option (D) is correct.
<h3>What is inequality?</h3>It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than, known as inequality.
The question is incomplete.
The complete question is in the picture, please find the attached picture.
We have:
The target temperature for a laboratory is 72° Fahrenheit. It can vary by up to 2°.
Target temperature = 72 degree Fahrenheit
It can vary by up to 2°. (the highest limit)
The temperature in the laboratory represented by t
Now,
inequality represents this situation is:
|t - 72| ≤ 2
Thus, the inequality |t - 72| ≤ 2 represents the target temperature for a laboratory is 72° Fahrenheit, and it can vary by up to 2° option (D) is correct.
Learn more about the inequality here:
#SPJ1
You might be interested in
Answer:
Step-by-step explanation:
we are given that given that 1/2T = 60 so T=120° so we also know R = 120 °
then W and S are also the same angle so 2z +240 = 360
2z = 120
z=60
W =60 °
S = 60 °
which makes sense b/c the small triangles also tell us that the sharp angles of the small triangles are 30 ° for the 30 , 60 90 triangle.
so by complementary angle we know that c = 60 °
we also know that a = 12 b/c all the small triangles are identical.
we also know that b= 90 ° also by complementary angle
we can also solve for length of SW and RT
cos(30)=adj / Hyp
12*Cos(30) = adj
12* /2 = adj
but the adjacent side is 2 times for SW so
SW = 12
for RT
sin(30) = Opp / hyp
12 * Sin(30) = Opp
12 * 1/2 = opp
but RT is times 2 again, sooo
RT = 12
you can also solve for the area of SRWT = 12 *12 = 144 units (what ever unties 12 is in) hmmm
That's all I can think of to solve for now :)
and
Solution:
Given value .
To evaluate the expression .
Using logarithmic rule:
We know that .
Using another logarithmic rule:
Hence and
.
Answer:
is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.
Step-by-step explanation:
Given the function
As the highest power of the x-variable is 3 with the leading coefficients of 1.
- So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.
solving to get the zeros
∵
as
so
Using the zero factor principle
if
Therefore, the zeros of the function are:
is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.
Therefore, the last option is true.