1. 8.96 x 105 I think
2. <span>4.25 x 10-4
</span>
One that can’t be solved so D
Answer:
243.6
Step-by-step explanation:
Answer:

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795
Step-by-step explanation:
Given
See attachment for class
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:

Where
Lower class interval
Upper class interval
So, we have:
Class 63-65:

Class 66 - 68:

When the computation is completed, the frequency distribution will be:

Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:


<em>See attachment for result of 1-VarStats</em>
Answer:
C
Step-by-step explanation:
1 since it's -1 inside it moves to the right
and it's positive 3 outside so it goes up 3