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Vsevolod [243]
2 years ago
7

If A: B = 5:7 and B: C = 3: 5, then A :B: C is: ​

Mathematics
2 answers:
Sindrei [870]2 years ago
7 0

Answer:

15 : 21 : 35

Step-by-step explanation:

Now, we see that both ratios contain B.

We need to find a common value for B so all values can be linked.

Multiply Ratio 1 by 3 and Ratio 2 by 7 :

⇒ A : B = 3 × 5 : 3 × 7 = 15 : 21

⇒ B : C = 7 × 3 : 7 × 5 = 21 : 35

Now we see B has the same value in both ratios.

Hence, the ratio we need to find is :

A : B : C = 15 : 21 : 35

mel-nik [20]2 years ago
6 0

Answer:

15:21:35

Step-by-step explanation:

to find this answer you must find a ratio in which both bs are the same

so

multiple a:b by 3 and b:c by 7

15:21 21:35

then you can put the bs together

15:21:35

that is your answer

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URGENT Solve 2(4 x + 3) < 5 x + 21. { x | x < 9} { x | x > -5} { x | x > -9} { x | x < 5}
zmey [24]

Answer:

{ x | x < 5}

Step-by-step explanation:

2(4 x + 3) < 5 x + 21

8x + 6 < 5x + 21

3x < 15

 x < 5

Answer

{ x | x < 5}

6 0
3 years ago
What is an extraneous solution to the equation b/b-3 -5/b=3/b-3 ?
storchak [24]
\frac{b}{b-3} - \frac{5}{b} = \frac{3}{b-3}  \\   \frac{ b^{2} -5(b-3)}{b(b-3)} =\frac{b}{b-3} \\  \frac{ b^{2} -5b+15}{b^2-3b} =\frac{b}{b-3} \\ (b-3)(b^{2} -5b+15)=b(b^2-3b) \\ b^3-8b^2+30b-45=b^3-3b^2 \\ 5b^2-30b+45=0 \\ b^2-6b+9=0 \\ (b -3)(b-3)=0 \\ b=3

To check: 3/3-3 - 5/3 = 3/0 - 5/3 which is not defined.

Therefore, b = 3 is an extraneous solution.
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3 years ago
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Jessica is a custodian at Oracle Arena. She waxes 20 \text{ m}^220 m 2 20, space, m, start superscript, 2, end superscript of th
Evgesh-ka [11]

Given that Jessica is a custodian at Oracle Arena.

She waxes 20 square meters space of the floor in 5/3 of an hour. Jessica waxes the floor at a constant rate means rate will remain fixed for any hour.

Now we have to find about how many square meters can she wax per hour.

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