2 goes into all the terms so;
2(-2x² + 7x - 3) now you could factor it:
2(-2x - 1)(x + 3)
The answer is : a^2=1 x 2^n-1
To check if it’s correct
a^2= 1 x 2^2-1
a^2 = 1x 2
a^2 = 2
Hope this helps!
Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
Lets replace the values into the the vertical motion formula to get:

Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:


Now we can apply the quadratic formula

where a=-16, b=122, and c=198


or


or


or

Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.
X is equal to 8. The work for that is on the attached picture.
In a circle, the arc is two times the length of the angle.
EFG = 98°
98 x 2 = 196
Minor arc EG = 196°
Hopefully this helps :)