Answer:
51.9 cm²
Step-by-step explanation:
From the diagram attached,
Area of the white region(segment)(A) = Area minor sector- area of the triangle
A = (πr²∅/360°)-(1/2r²sin∅)............... Equation 1
Where r = radius of the circle, Ф = reflex angle formed at the center of the circle, π = pie
From the question,
Given: r = 7 cm, Ф = 150°
Constant: π = 22/7
Substitute these values into equation 1
A = [(22/7)×7²×150/360]-[(1/2)×7²×sin150]
A = 64.17-12.25
A = 51.92
A = 51.9 cm²
Answer:
(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.
(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.
(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.
Step-by-step explanation:
Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.
If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:
The three populations has the following proportions:
p₁ = 0.10
p₂ = 0.30
p₃ = 0.50
(1)
Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:
Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.
(2)
Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:
Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.
(3)
Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:
Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.