Answer:
They both have an infinite number of solutions.
Step-by-step explanation:
Given system of equations:
a) 2x + 4y = 15
b) 6x + 12y = 45
Slope-intercept form: y = mx + b
<u>where:</u>
- m is the slope
- b is the y-intercept (when x = 0)
Rewrite <em>both</em> equations into slope-intercept form:
<em>a) 2x + 4y = 15 </em>
⇒ 2x + 4y = 15 [subtract 2x from both sides]
⇒ 2x - 2x + 4y = 15 - 2x
⇒ 4y = - 2x + 15 [divide both sides by 4]
⇒ 4y ÷ 4 = (-2x ÷ 4) + (15 ÷ 4)
![\sf \implies y = -\dfrac{1}{2}x\ + \dfrac{15}{4} \ or \ y=-0.5x\ + 3.75](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%20y%20%3D%20-%5Cdfrac%7B1%7D%7B2%7Dx%5C%20%2B%20%5Cdfrac%7B15%7D%7B4%7D%20%5C%20or%20%5C%20y%3D-0.5x%5C%20%2B%203.75)
<em>b) 6x + 12y = 45</em>
⇒ 6x + 12y = 45 [subtract 6x from both sides]
⇒ 6x - 6x + 12y = 45 - 6x
⇒ 12y = - 6x + 45 [divide both sides by 12]
⇒ 12y ÷ 12 = (-6x ÷ 12) + (45 ÷ 12)
![\sf \implies y = -\dfrac{1}{2}x\ + \dfrac{15}{4} \ or \ y=-0.5x\ + 3.75](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%20y%20%3D%20-%5Cdfrac%7B1%7D%7B2%7Dx%5C%20%2B%20%5Cdfrac%7B15%7D%7B4%7D%20%5C%20or%20%5C%20y%3D-0.5x%5C%20%2B%203.75)
New equations:
![\sf a)\ y = -\dfrac{1}{2}x\ + \dfrac{15}{4} \ or \ y=-0.5x\ + 3.75\\\\\sf b)\ y = -\dfrac{1}{2}x\ + \dfrac{15}{4} \ or \ y=-0.5x\ + 3.75](https://tex.z-dn.net/?f=%5Csf%20a%29%5C%20y%20%3D%20-%5Cdfrac%7B1%7D%7B2%7Dx%5C%20%2B%20%5Cdfrac%7B15%7D%7B4%7D%20%5C%20or%20%5C%20y%3D-0.5x%5C%20%2B%203.75%5C%5C%5C%5C%5Csf%20b%29%5C%20y%20%3D%20-%5Cdfrac%7B1%7D%7B2%7Dx%5C%20%2B%20%5Cdfrac%7B15%7D%7B4%7D%20%5C%20or%20%5C%20y%3D-0.5x%5C%20%2B%203.75)
Both equations have the same slope (-½), and y-intercept (3.75). Therefore, they both have an infinite number of solutions.
System of equations can have the following:
<u><em>No Solution:</em></u> the same slope (both lines will be parallel)
<u><em>One Solution:</em></u> different slopes and different y-intercepts
<u><em>Infinitely Many Solutions:</em></u> the same slope and y-intercept
Learn more about system of equations here:
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