Answer:
<h2>(3, -2)</h2>
Step-by-step explanation:
Put the coordinates of the points to the inequality and check:
y < -1/2x + 2
for (2, 3) → x = 2, y = 3
3 < -1/2(2) + 2
3 < -1 + 2
3 < 1 FALSE
============================
for (2, 1) → x = 2, y = 1
1 < -1/2(2) + 2
1 < -1 + 2
1 < 1 FALSE
============================
for (3, -2) → x = 3, y = -2
-2 < -1/2(3) + 2
-2 < -1.5 + 2
-2 < 0.5 TRUE
============================
for (-1, 3) → x = -1, y = 3
3 < -1/2(-1) + 2
3 < 1/2 + 2
3 < 2 1/2 FALSE
Did this wrong sorry I thought it was greatest to least.
9514 1404 393
Answer:
y -1 = -1(x -2)
Step-by-step explanation:
The slope of the line through the two points can be found from the slope formula:
m = (y2 -y1)/(x2 -x1)
m = (5 -1)/(-2 -2) = 4/-4 = -1
The point-slope equation for a line through point (h, k) with slope m is ...
y -k = m(x -h)
You have (h, k) = (2, 1) and m = -1. Putting these values into the form gives ...
y -1 = -1(x -2)
_____
<em>Additional comment</em>
Your problem statement already has two of the three values filled in, so you only need to enter the x-coordinate of the first point: 2.
Recall that
where 
is the angle between the vectors 
whose magnitudes are 
, respectively.
We have
