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11Alexandr11 [23.1K]
2 years ago
7

A long novel is opened to a random page; the probability that the page is numbered something between 21 and 31.

Mathematics
1 answer:
Harrizon [31]2 years ago
5 0

Using the uniform distribution, considering that the novel has 435 pages, the probability that the page is numbered something between 21 and 31 is:

p = \frac{10}{435}

<h3>What is the uniform probability distribution?</h3>

It is a distribution with two bounds, a and b, in which each outcome is equally as likely.

The probability of finding a value between c and d is:

P(c \leq X \leq d) = \frac{d - c}{b - a}

Researching the problem on the internet, it is found that the novel has 435 pages, hence a = 0, b = 435, and the probability that the page is numbered something between 21 and 31 is given by:

P(21 \leq X \leq 31) = \frac{31 - 21}{435 - 0} = \frac{10}{435}

More can be learned about the uniform distribution at brainly.com/question/13889040

#SPJ1

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Answer:

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Geometry = 51

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None = 5

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Required

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The attached image illustrates the question.

For French only (x), we have:

x + 7 -2+10-2+2=27

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Collect like terms

x =- 15+27

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y+10-2+15-2+2=51

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Collect like terms

y=-23+51

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For History only (z), we have:

z +15-2+7-2+2=38

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z =-20+38

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1\ subject = x+y+z

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