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Kaylis [27]
2 years ago
11

Solve for x in the equation 4/x-3=x

Mathematics
2 answers:
Nutka1998 [239]2 years ago
8 0

Answer:

jenejebdjdndnr

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r

r

r

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svetlana [45]2 years ago
5 0

Answer:

Step-by-step explanation:

Comment

Multiply through by x - 3

Then factor the result

4*(x - 3) / (x - 3) = x*(x - 3)

4 = x * (x - 3 )                          Remove the brackets

4 = x^2 - 3x                            Subtract 4 from both sides

4-4 = x^2 - 3x - 4                    Simplify

0 = x^2 - 3x- 4

This factors

0=(x - 4)(x + 1)

Answer

x - 4 = 0

x = 4

x+ 1 = 0

x = - 1

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find the smaller of 2 consecutive integers,x, if the sum of the smaller and 6 times the larger is -29
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Explanation:-

Let the first consecutive integer be x and the second consecutive integer be x+1.

According to the given question:-

x+6(x+1)= -29

⇒x+6x+6= -29   [distributive law]

⇒x+6x= -29-6    [subtract 6 on the both sides]

⇒7x= -35      [combining like terms ]

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nikitadnepr [17]

Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

The first one as it is a sloping straight  passing through the origin.

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