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Nana76 [90]
3 years ago
13

A family spends 1/10 of its annual income for housing, 1/4 for food and clothes, 1/5 for general expenses, and 2/15 for entertai

nment. What fractional part of their income is spent on these items altogether?
A. 1/7
B. 6/41
C. 41/60
D. 11/12
Mathematics
2 answers:
Mkey [24]3 years ago
8 0
C is the right answer
Thank you
AlexFokin [52]3 years ago
6 0
Add all the fractions together:
to do this find the lcd:
which is 60
1/10 = 6/60
1/4= 15/60
1/5= 12/60
2/15= 8/60
add them together
(6+15+12+8)/60
41/60 or C is the answer

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In the diagram below, trapezoid ABCD maps to trapezoid A’B’C’D’
snow_tiger [21]

Answer:

C'

Step-by-step explanation:

Given

ABCD to A'B'C'D'

Required

Corresponding angle of C

ABCD to A'B'C'D' means that the following angles are corresponding

A \to A'

B \to B'

C \to C'

D \to D'

Hence, C' corresponds to C

6 0
2 years ago
Read 2 more answers
Solve c: P = a+b+c+d / 4
m_a_m_a [10]

Answer:

  • as written: c = P - a - b - d/4
  • with parentheses: c = 4P - a - b - d

Step-by-step explanation:

The meaning of the given expression is ...

  P = a + b + c + (d/4)

To solve for c, subtract all the terms on the right side not containing c.

  P -(a + b + (d/4)) = c

  c = P - a - b - (d/4)

_____

In such equations, parentheses are commonly missing. If that is the case here, then first we undo the division by 4, then we subtract the "not c" terms.

  P = (a + b + c + d)/4 . . . . maybe what you meant

  4P = a + b + c + d . . . . . . multiply by 4

  4P - (a +b +d) = c

  c = 4P -a -b -d

8 0
4 years ago
YALL PLEASE HELP MY BIRTHDAY IS CANCELED IF I DONT GET THIS FORM DONE!!!
Zepler [3.9K]

Answer:

It is option 1

Step-by-step explanation:

domain is x and the two points range from -1 to 3. The picture quality wasn't that good so if I miss read sry. haha

3 0
3 years ago
If sum of first 6 digits of AP is 36 and that of the first 16 terms is 255,then find the sum of first ten terms.
Cloud [144]

Answer:

100

Step-by-step explanation:

We have the sum of first n terms of an AP,

Sn = n/2 [2a+(n−1)d]

Given,

36= 6/2 [2a+(6−1)d]

12=2a+5d ---------(1)

256= 16/2 [2a+(16−1)d]

32=2a+15d ---------(2)

Subtracting, (1) from (2)

32−12=2a+15d−(2a+5d)

20=10d ⟹d=2

Substituting for d in (1),

12=2a+5(2)=2(a+5)

6=a+5 ⟹a=1

∴ The sum of first 10 terms of an AP,

S10 = 10/2 [2(1)+(10−1)2]

S10 =5[2+18]

S10 =100

This is the sum of the first 10 terms.

Hope it will help.

4 0
3 years ago
Read 2 more answers
Planes X and Y and points J, K, L, M, and N are shown. Exactly how many planes contain points J, K, and N? 0 1 2 3
defon
0, because 3 points make a line.
7 0
3 years ago
Read 2 more answers
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