It could be ‘save as’ or ‘your work’, not completely sure
Incomplete question. The Options read;
A. The year purchased
B. Brian's classmates
C. The amount of memory
D. The type of operating system
Answer:
<u>B. Brian's classmates</u>
Explanation:
<em>Remember,</em> the question is concerned about <em>"the individuals"</em> in the data set, <u>so the year they purchased their computer, neither is the amount of memory of the computer and the type of operating system can be classified as individuals in the data set.</u>
Hence, we can correctly say, only Brian's classmates are the individuals in this data set.
Answer:
There is only one modification in the above loop i.e. while loop should be like this--
while (i != n)
{
sum+=arr[i]; // Line 1, In question segment it is line 2.
i++; // Line 2, In question segment it is line 1.
}
Output:
Now if the array input is 1,2,3,4,5 then the output is 15.
Explanation:
In the above question, all the line of the segment is right except the body of the loop because--
- The First line of the loop is increment statement which increments the value of "i" variable from 1 and the value of "i" variable will be 1 in the first iteration of the loop
- The second line starts to add the value from 1'st index position of the array. Hence the segment gives the wrong answer. It adds the arr[1] to arr[n-1].
- So I interchanged both lines of the while loop as shown in the answer part. I make the line 1 (In question segment) as line 2(In answer part) and line 2 (In question segment) as line 1 (In answer part).
Now It gives the correct output because it can add arr[0] to arr[n-1].
Explanation:
A.)
we have two machines M1 and M2
cpi stands for clocks per instruction.
to get cpi for machine 1:
= we multiply frequencies with their corresponding M1 cycles and add everything up
50/100 x 1 = 0.5
20/100 x 2 = 0.4
30/100 x 3 = 0.9
CPI for M1 = 0.5 + 0.4 + 0.9 = 1.8
We find CPI for machine 2
we use the same formula we used for 1 above
50/100 x 2 = 1
20/100 x 3 = 0.6
30/100 x 4 = 1.2
CPI for m2 = 1 + 0.6 + 1.2 = 2.8
B.)
CPU execution time for m1 and m2
this is calculated by using the formula;
I * CPI/clock cycle time
execution time for A:
= I * 1.8/60X10⁶
= I x 30 nsec
execution time b:
I x 2.8/80x10⁶
= I x 35 nsec
