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2 years ago

Find the 9th term of the geometric sequence 8,32,128,

1 answer:

7 0

$\text{First term,}~ a = 8\\\\\text{Common ratio,}~ r= \dfrac{32}8 = 4\\\\\text{nth term} = ar^{n-1} \\\\\text{9th term} = 8\cdot 4^{9-1}\\\\\\~~~~~~~~~~~~~=8 \cdot 4^8\\\\\\~~~~~~~~~~~~~=524288\\\\\text{The 9th of the geometric sequence is 525288.}$

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Given the points (5,4) and (10, 11)<br> a.what is the slope? <br> b.what is the y-intercept?

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4 years ago

If p(x) = x 2 + 7x + 3 is divided by x + 4, the remainder is ?

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4 years ago

Please help! x^3 +y^3=9

Crank

Step-by-step explanation:

Taking the derivative of both sides with respect to x, we get

$\dfrac{d}{dx}(x^3 + y^3) = \dfrac{d}{dx}(3)$

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3 years ago

Quick algebra 1 question for 10 points!

Mars2501 [29]

The factors of the given quadratic expression, 2x² - 4x - 16, are 2, (x +2), and (x -4)

<h3>Factoring a Quadratic expression </h3>

From the question, we are to determine the each of the factors of the given quadratic expression

The given quadratic expression is

2x² - 4x - 16

Factoring

2x² - 4x - 16

First, factor out 2

That is,

2(x² - 2x - 8)

Now, we will factor x² - 2x - 8
x² - 2x - 8

x² - 4x + 2x - 8

x(x - 4) +2(x -4)

(x +2)(x -4)

Thus,

2x² - 4x - 16 = 2(x +2)(x -4)

Hence, the factors of the given quadratic expression, 2x² - 4x - 16, are 2, (x +2), and (x -4)

Learn more on Factoring a quadratic expression here: brainly.com/question/52959

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1 year ago

Read 2 more answers

M+2/3=1/4m-1<br><br><br>what the formula used to find the value of m?

zimovet [89]

<u>Answer:</u>

The value of m is $\frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6}$ by using quadratic formula

<u>Solution:</u>

Given, expression is $m+\frac{2}{3}=\frac{1}{4 m}-1$

Now, we have to solve the above given expression.

$\text { Now, } \mathrm{m}+\frac{2}{3}=\frac{1}{4 m}-1$

By multiplying the equation with m, we get

$\begin{array}{l}{m^{2}+\frac{2}{3} m+m=\frac{1}{4}} \\\\ {m^{2}+m\left(\frac{2}{3}+1\right)=\frac{1}{4}} \\\\ {m^{2}+\frac{5}{3} m=\frac{1}{4}}\end{array}$

$\begin{array}{l}{12 m^{2}+20 m=3} \\ {12 m^{2}+20 m-3=0}\end{array}$

Now, let us use quadratic formula

$\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in our problem, a = 12, b = 20, c = -3

$\begin{array}{l}{m=\frac{-20 \pm \sqrt{20^{2}-4 \times 12 \times(-3)}}{2 \times 12}} \\\\ {=\frac{-20 \pm \sqrt{400+144}}{24}} \\\\ {=\frac{-20 \pm \sqrt{544}}{24}} \\\\ {=\frac{-20 \pm 4 \sqrt{34}}{24}=\frac{-5 \pm \sqrt{34}}{6}} \\\\ {=\frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6}}\end{array}$

Hence the value of m is $\frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6}$ by using quadratic formula

7 0

4 years ago