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galina1969 [7]
2 years ago
8

Find the 9th term of the geometric sequence 8,32,128,

Mathematics
1 answer:
zvonat [6]2 years ago
7 0

\text{First term,}~ a = 8\\\\\text{Common ratio,}~ r= \dfrac{32}8 = 4\\\\\text{nth term} = ar^{n-1} \\\\\text{9th term} = 8\cdot 4^{9-1}\\\\\\~~~~~~~~~~~~~=8 \cdot 4^8\\\\\\~~~~~~~~~~~~~=524288\\\\\text{The 9th of the geometric sequence is 525288.}

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Answer:

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The first 4 digits are simple, you multiply the first digit of the equation by the 2nd digit and then for the other 2 you multiply the first digit of the equation by the 3rd digit.

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6 * 2 = 12

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Then the last 2 digits are the sum of the products of the 1 and 2 and 1 and 3 and subtract it by the 2

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3 years ago
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Read 2 more answers
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