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3 years ago

What is the slope of the line that passes through the points (3, 6)(3,6) and (1, 2) ?(1,2)

Mathematics

1 answer:

morpeh [17]3 years ago

7 0

Answer:

-2

Step-by-step explanation:

Using the slope theorem:

$m=\frac{y_{1}-y_{0}}{x_{1}-x_{0}}$

$\frac{6-2}{1-3} = \frac{4}{-2} =-2$

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Una empresa embotelladora de gaseosas lanzará su propia bebida "Delicia" de un litro a un costo variable de S/ 2.50 por unidad,

KIM [24]

Por la ecuación de utilidad, necesitamos una producción de 7,667 botellas de un litro de capacidad para obtener un total de utilidades de S/ 30.000.

<h3>¿Cómo determinar las utilidades por la venta de bebidas gaseosas?</h3>

Las utilidades (U') se obtienen de sustraer los costes de producción (Cp) a las utilidades <em>netas</em> (U). Los costes de producción (Cp) son la suma de costes <em>variables</em> (C') y costes <em>fijos </em>(C). y la utilidades <em>netas</em> proceden de la venta de botellas. En consecuencia, tenemos la siguiente expresión:

U' = U - Cp

U' = U - C' - C

A continuación, desarrollamos y resolvemos la ecuación resultante:

30000 = 4.50 · x - 2.50 · x - 18500

1.50 · x = 11500

x = 7667

Por la ecuación de utilidad, necesitamos una producción de 7,667 botellas de un litro de capacidad para obtener un total de utilidades de S/ 30.000.

Para saber sobre utilidades: brainly.com/question/16933668

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6 0

2 years ago

Find the equation of the line through ( - 10, - 8) that is perpendicular to the line through (10,6), (5,5).

Furkat [3]

Answer:

y=-5x-58

Step-by-step explanation:

The equation of a line in slope-intercept form is y=mx+b where m is the slope and b is the y-intercept.

Perpendicular lines have opposite reciprocal slopes.

Anyways we need to find the slope of the line going through (10,6) and (5,5).

To find the slope, we are going to line up the points vertically and subtract vertically, then put 2nd difference over 1st difference. Like so:

( 10 , 6)

- ( 5 , 5)

------------------

5 1

So the slope of the line through (10,6) and (5,5) is 1/5.

The slope of a line that is perpendicular will be the opposite reciprocal of 1/5.

The opposite reciprocal of 1/5 is -5.

The line we are looking for is y=-5x+b where we need to find the y-intercept b.

y=-5x+b goes through (-10,-8)

So we can use (x,y)=(-10,-8) to find b in y=-5x+b.

y=-5x+b with (x,y)=(-10,-8)

-8=-5(-10)+b

-8=50+b

Subtract 50 on both sides:

-8-50=b

-58=b

So the equation is y=-5x-58

4 0

4 years ago

Need help with Writeing the quadratic function with at two zero where x = ‒2 and x = 0.

Pachacha [2.7K]

We can create the equation like this:
(x +2) * (x +0)
x^2 + 2x + 0 = 0

8 0

3 years ago

The function f(x) = –x2 – 4x + 5 is shown on the graph. On a coordinate plane, a parabola opens down. It goes through (negative

sertanlavr [38]

The true statement about the function f(x) = -x² - 4x + 5 is that:

The range of the function is all real numbers less than or equal to 9.

<h3 /><h3>What is the domain and range for the function of y = f(x)?</h3>

The domain of a function is the set of given values of input for which the function is valid and true.

The range is the dependent variable of a given set of values for which the function is defined.

The domain of the function: f(x) = -x² - 4x + 5 are all real number from -∞ to +∞

For a parabola ax² + bx + c with the vertex $\mathbf{(x_v,y_v)}$

If a < 0, then the range is f(x) ≤ $\mathbf{y_v}$

If a > 0, then the range f(x) ≥ $\mathbf{y_v}$

Here; a = -1,

The vertex for an up-down facing parabola for a function y = ax² + bx + c is:

$\mathbf{x_v = -\dfrac{b}{2a}}$

Thus,

vertex $\mathbf{(x_v,y_v)}$ = (-2, 9)

Range: f(x) ≤ 9

Therefore, we can conclude that the range of the function is all real numbers less than or equal to 9.

Learn more about the domain and range of a function here:

brainly.com/question/26098895

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5 0

2 years ago

Evaluate (-32) 7/5<br> The solution is

kobusy [5.1K]

Answer:

- 224/5

Step-by-step explanation:

DECIMEL FORM = -44 4/5

8 0

3 years ago