1)11x = 22 x = 2
2)-1/2x = 25. x = -50
3)-4/5f = -14. f = 17.5
4)-6x = -6. x = 1
5) 8x = 200. x = 25 days
Y=3x+1! It is parallel because they have the same slope and it contains the point (2,7)
Answer:
![Leg\ 1 = 8](https://tex.z-dn.net/?f=Leg%5C%201%20%3D%208)
![Leg\ 2 = 15](https://tex.z-dn.net/?f=Leg%5C%202%20%3D%2015)
Step-by-step explanation:
Given: See Attachment
Required
Determine the length of the legs
To do this, we apply Pythagoras theorem.
![Hyp^2 = Adj^2 + Opp^2](https://tex.z-dn.net/?f=Hyp%5E2%20%3D%20Adj%5E2%20%2B%20Opp%5E2)
In this case:
![17^2 = x^2 + (2x- 1)^2](https://tex.z-dn.net/?f=17%5E2%20%3D%20x%5E2%20%2B%20%282x-%201%29%5E2)
Open Bracket
![17^2 = x^2 + 4x^2- 2x-2x + 1](https://tex.z-dn.net/?f=17%5E2%20%3D%20x%5E2%20%2B%204x%5E2-%202x-2x%20%2B%201)
![17^2 = 5x^2 - 4x + 1](https://tex.z-dn.net/?f=17%5E2%20%3D%205x%5E2%20-%204x%20%2B%201)
![289= 5x^2 - 4x + 1](https://tex.z-dn.net/?f=289%3D%205x%5E2%20-%204x%20%2B%201)
Collect Like Terms
![5x^2 - 4x + 1 - 289 = 0](https://tex.z-dn.net/?f=5x%5E2%20-%204x%20%2B%201%20-%20289%20%3D%200)
![5x^2 - 4x - 288 = 0](https://tex.z-dn.net/?f=5x%5E2%20-%204x%20-%20288%20%3D%200)
Solving using quadratic formula:
![x = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-b%5C%C2%B1%5Csqrt%7Bb%5E2%20-%204ac%7D%7D%7B2a%7D)
So:
or ![x = -7.2](https://tex.z-dn.net/?f=x%20%3D%20-7.2)
Since, x can't be negative, then:
![x = 8](https://tex.z-dn.net/?f=x%20%3D%208)
One of the leg is:
![Leg\ 1 = x](https://tex.z-dn.net/?f=Leg%5C%201%20%3D%20x)
![Leg\ 1 = 8](https://tex.z-dn.net/?f=Leg%5C%201%20%3D%208)
![Leg\ 2 = 2x - 1](https://tex.z-dn.net/?f=Leg%5C%202%20%3D%202x%20-%201)
![Leg\ 2 = 2*8 - 1](https://tex.z-dn.net/?f=Leg%5C%202%20%3D%202%2A8%20-%201)
![Leg\ 2 = 16 - 1](https://tex.z-dn.net/?f=Leg%5C%202%20%3D%2016%20-%201)
![Leg\ 2 = 15](https://tex.z-dn.net/?f=Leg%5C%202%20%3D%2015)
Step-by-step explanation:
2i/3-5i
2i/7i
answere-2i/7i
Answer:
A. 2(x2 - 1) = 2(y2 - y1)
Step-by-step explanation:
Perimeter
P = 2W + 2L
W = √(x2 - x1)^2 = x2 - 1
L = √(y2 - y1)^2 = y2 - y1
So
P = 2(x2 - 1) = 2(y2 - y1)
Answer is A.
2(x2 - 1) = 2(y2 - y1)