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AleksAgata [21]
2 years ago
15

(2i)/(3-5i) HELP ASAP --- algebra 2 question

Mathematics
1 answer:
ycow [4]2 years ago
5 0

Step-by-step explanation:

2i/3-5i

2i/7i

answere-2i/7i

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The distance between Cincinnati,Ohio and Charlotte,North Carolina,is about 336 miles. The distance between Cincinnati and Chicag
navik [9.2K]

336+247=583miles

charlotte-chicago

charlotte-ohio=336

ohio- Chicago-247

so charlotte-chicago=583miles

6 0
3 years ago
Please Help? A circle has an arc length of 5π in. The central angle for this arc measures π/3 radians. What is the area of the a
Zielflug [23.3K]

Answer:

The area of the associated sector is \frac{25}{24}\pi \ in^{2}  

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The circumference of a circle is equal to

C=2\pi r

we have

C=5\pi\ in

substitute and solve for r

5\pi=2\pi r

r=2.5\ in

step 2

Find the area of the circle

we know that

The area of the circle is equal to

A=\pi r^{2}

we have

r=2.5\ in

substitute

A=\pi (2.5^{2})=6.25\pi\ in^{2}

step 3

Find the area of the associated sector

we know that

2\pi\ radians subtends the complete circle of area 6.25\pi\ in^{2}

so

by proportion

Find the area of a sector with a central angle of \pi/3\ radians

\frac{6.25\pi }{2\pi} =\frac{x}{\pi/3}\\x=6.25*(\pi/3)/2\\ \\x=\frac{25}{24}\pi \ in^{2}

8 0
3 years ago
A stone is a British unit of weight equivalent to 14 pounds. After losing 1 1/2 stone. Jim is now 85% of his original weight. Wh
evablogger [386]

Answer:

Jim's current weight = 119 pounds

Step-by-step explanation:

1 Stone = 14 pounds

1\frac{1}{2} stone = 1.5 stone

1.5 stone = 1.5 (14 pounds) = 21 pounds

Jim lost 21 pounds

Let X be Jim's Original Weight

Y be his present weight

As per given statement in the Question:

After losing 1.5 stones (21 pounds of weight) Jim now weighs Y

Present weight = original weight - 21

Y = X -21     <u>                                                    Equation 1</u>

Also Current Weight = 85 % (Original weight)

Y = 85 % (X) =\frac{85X}{100}

Y=\frac{85X}{100}

put in Equation 1

\frac{85X}{100} = X-21

85X = (X-21) 100

85 X = 100 X -2100

or

2100 = 100 X - 85X

2100 = 15X

or

15 X = 2100

X=\frac{2100}{15}

X= 140 pounds ( Original Weight)

Current Weight = Y = Original weight - 21 <u><em>(From Equation 1)</em></u>

Y = X -21

Y = 140 -21

Y = 119 pounds (Current Weight)

5 0
3 years ago
41,000 rounded to the nearest 10,000
zloy xaker [14]
40,000 is the asnwer
3 0
3 years ago
4TH TIME ASKING THIS!!! Please help me! Someone pleaseeee. I need the correct answers. I don’t want to fail
Alexeev081 [22]

Answer:

The functions are inverses; f(g(x)) = x ⇒ answer D

h^{-1}(x)=\sqrt{\frac{x+1}{3}} ⇒ answer D

Step-by-step explanation:

* <em>Lets explain how to find the inverse of a function</em>

- Let f(x) = y

- Exchange x and y

- Solve to find the new y

- The new y = f^{-1}(x)

* <em>Lets use these steps to solve the problems</em>

∵ f(x)=\sqrt{x-3}

∵ f(x) = y

∴ y=\sqrt{x-3}

- Exchange x and y

∴ x=\sqrt{y-3}

- Square the two sides

∴ x² = y - 3

- Add 3 to both sides

∴ x² + 3 = y

- Change y by f^{-1}(x)

∴ f^{-1}(x)=x^{2}+3

∵ g(x) = x² + 3

∴ f^{-1}(x)=g(x)

∴ <u><em>The functions are inverses to each other</em></u>

* <em>Now lets find f(g(x))</em>

- To find f(g(x)) substitute x in f(x) by g(x)

∵ f(x)=\sqrt{x-3}

∵ g(x) = x² + 3

∴ f(g(x))=\sqrt{(x^{2}+3)-3}=\sqrt{x^{2}+3-3}=\sqrt{x^{2}}=x

∴ <u><em>f(g(x)) = x</em></u>

∴ The functions are inverses; f(g(x)) = x

* <em>Lets find the inverse of h(x)</em>

∵ h(x) = 3x² - 1 where x ≥ 0

- Let h(x) = y

∴ y = 3x² - 1

- Exchange x and y

∴ x = 3y² - 1

- Add 1 to both sides

∴ x + 1 = 3y²

- Divide both sides by 3

∴ \frac{x + 1}{3}=y^{2}

- Take √ for both sides

∴ ± \sqrt{\frac{x+1}{3}}=y

∵ x ≥ 0

∴ We will chose the positive value of the square root

∴ \sqrt{\frac{x+1}{3}}=y

- replace y by h^{-1}(x)

∴ h^{-1}(x)=\sqrt{\frac{x+1}{3}}

4 0
3 years ago
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