Question

Given that W is directly proportional to the square of V, and W = 320 when V = 8, find W when V = 9.

Answer 1

The value of W when V = 9 is 405

How to solve for W?

The variation is a direct variation from W to V^2.

This means that:

W = kV^2

Where k is the constant of variation.

W = 320 when V = 8 means that:

320 = k * 8^2

Evaluate

320 = 64k

Divide both sides by 64

k = 5

Substitute k = 5 in W = kV^2

W = 5V^2

When V = 9, we have:

W = 5 * 9^2

Evaluate

W = 405

Hence, the value of W when V = 9 is 405

Read more about direct variation at:

brainly.com/question/6499629

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