Question

Find the value of x pls help thank u so much

Answer 1

Answer:

$\sqrt{66}$

Step-by-step explanation:

By geometric mean property:

$BD = \sqrt{6 \times 5} = \sqrt{30} \\ \\ In \: \triangle ABD: \\ by \: pythagoras \: theorem : \\ \\ AD^2 = AB^2 + BD^2 \\ \\ {x}^{2} = {6}^{2} + {( \sqrt{30}) }^{2} \\ \\ {x}^{2} = 36 + 30 \\ \\ {x}^{2} = 66 \\ \\ x = \sqrt{66}$

Answer 2

Answer:

7.81

Step-by-step explanation: