Given:
The equation of a line is:
A line is parallel to the given line and passes through the point (3,-4).
To find:
The equation of the line in the slope intercept form.
Solution:
The slope intercept form of a line is:
...(i)
Where, m is the slope and b is the y-intercept of the line.
We have,
...(ii)
On comparing (i) and (ii), we get
Slope of the given line is 1.
We know that the slopes of parallel lines are equal. So, the slope of the required line is 1.
The required line passes through the point (3,-4) with slope 1. So, the equation of the required line is:
Subtracting 4 from both sides, we get
Therefore, the equation of the required line is .
Answer:
All I got is this I'm sorry
Step-by-step explanation:
Exact form -13/3
Decimal form -4.3
Mixed -4 1/3
Answer:
d = 0.33
Step-by-step explanation:
First off, you want to get like terms next to each other. We'll move the numbers with variables on one side and normal numbers on the other. Since we're changing the sides of the equal sign they're on, this also changes whether their positive or negative.
d - d - 2d + 3d = 10 -7 + 8 - 10
Now that they're together, we can add or subtract them. The variables without numbers can be ones for this equation.
3d = 1
Now we divide 1 by 3 to find what d equals.
3d/3 = 1/3
d = 0.33
For this question, you didn't gave enough details.
Read the function given by the question first.
After that substitute x with - 8.
Answer: 1/cos θ
Step-by-step explanation:
From basic trigonometry, csc θ is the short form of cosec θ which is further expressed as
csc θ = 1/sin θ
Also,
tan θ = sin θ/cos θ
Knowing this basis of trigonometry makes the simplification easy for us.
Firstly, expressing the equation in terms of sin θ and cos θ,
The equation becomes csc θ * tan θ = [1/sin θ] * [sin θ/ cos θ]
Further simplifying by multiplication, our answer becomes
1/cos θ
