2(x + 3) = x - 4 Solve this equation
2 answers:
Hii!
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x=-10
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Let's distribute 2 first.
.
Now subtract 6 from both sides.
Now we subtract x from both sides.
Hope that this helped! Best Wishes.
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I assume there are some plus signs that aren't rendering for some reason, so that the plane should be 
.
You're minimizing
subject to the constraint 
. Note that 
and 
attain their extrema at the same values of 
, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.
The Lagrangian is
Take your partial derivatives and set them equal to 0:
Adding the first three equations together yields
and plugging this into the first three equations, you find a critical point at
.
The squared distance is then
, which means the shortest distance must be 
.
You're minimizing
The Lagrangian is
Take your partial derivatives and set them equal to 0:
Adding the first three equations together yields
and plugging this into the first three equations, you find a critical point at
The squared distance is then
Answer:
The farthest point is the Challenger Deep
Step-by-step explanation:
Given
Solving (a): The sea level
Both elevations had signs in front of them.
The sea level is the point at the neutral level, neither positive nor negative.
Hence:
Solving (b): Farthest Point.
The farthest point is the one with the highest magnitude.
Comparing
to
-35,797 ft has the highest magnitude.
Hence:
<em>The farthest point is the Challenger Deep</em>