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Anna11 [10]
3 years ago
12

PLEASE HELP

Mathematics
1 answer:
aliina [53]3 years ago
6 0
Would you be seven?
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What's the mean median and range of 5, 15, 10, 20,15 10, 15
Korvikt [17]

Answer:

Mean = 12.85714

Median = 15

Range = 15

Step-by-step explanation:

Mean:

5 + 15 + 10 + 20 + 15 + 10 + 15 = 90

90 / 7 = 12.85714

Median:

5, 10, 10, 15, 15, 15, 20

Median = 15

Range:

20 - 5 = 15

6 0
3 years ago
URGENT!!!!!!!! PLEASE HELP ASAP TIMED!!!!!!!!!!!!!!!
barxatty [35]

Step-by-step explanation:

Given that,

Perpendicular = 17 units

Hypotenuse = 25 units

We need to find the value of x.

Using Pythagoras theorem to find x.

Hypotenuse² = base²+perpendicular²

25² = x² + 17²

x = 18.3 units

So, the value of x is equal to 18.3 units. No, the sides do not form a Pythagorean triplet.

4 0
2 years ago
Find the product of each pair of complex conjugates.<br>(3+8i)(3-8i)=
sdas [7]
3*3=9

3 *-8i = -24i

8i *3 =24i

8i*-8i = -64i^2 or i^2 =-1. -64*-1=64

-24i + 24i =0

9+64= 73

Answer 73
4 0
3 years ago
Read 2 more answers
Perform each indicated operation
MissTica

Answer: \frac{x+6}{x-4}

Step-by-step explanation:

First you need know some general formuals of factorization such as

x^3+y^3=(x+y)(x^2-xy+y^2) so you have x^3+64=X^3+4^3=(x+4)(x^2-4x+4^2)

And, x^2-y^2=(x-y)(x+y) so you have 2x^2-32=2(x^2-16)=2(x^2-4^2)=2(x+4)(x-4)

If you use them, then you can modify your equations such as

\frac{x^3+64}{2x^2-32} ÷ \frac{x^2-4x+16}{2x+12} = \frac{(x+4)(x^2-4x+4^2)}{2(x+4)(x-4)} ÷ \frac{x^2-4x+16}{2(x+6)}  =  \frac{(x+4)(x^2-4x+4^2)}{2(x+4)(x-4)} . \frac{2(x+6)}{{x^2-4x+16}} = \frac{1}{x-4}.\frac{x+6}{1}=\frac{x+6}{x-4}

4 0
3 years ago
8x-1&lt;15<br> NO one will help plss someone hellpppp
romanna [79]

Answer:

x < 2

Step-by-step explanation:

8x -1 < 15

8x -1 (+ 1) < 15 (+ 1)

8x < 16

\frac{8x}{8} < \frac{16}{8}

x < 2

7 0
3 years ago
Read 2 more answers
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