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2 years ago

Mr wong predicted that he would sell 45 automobiles , he actually sold 48

Mathematics

1 answer:

dolphi86 [110]2 years ago

7 0

Answer:

well done mr wong lol

Step-by-step explanation:

what's the question is it the percent he beat his prediction?

if it is then its 48 divided by 45 times 100

this equals 106.67%

then take this away from his prediction percent originally which is 100%

106.67-100= 6.67%

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Jenny bought t toy cars. The cars came in 9 packages. Write an expression that shows how many toy cars were in each package.

Annette [7]

T/9

you divide the number of cars, t, by the number of packages it came in, 9

6 0

4 years ago

Read 2 more answers

In right ABC, AN is the altitude to the hypotenuse. FindBN, AN, and AC,if AB =2 5 in, and NC= 1 in.

Rama09 [41]

From the statement of the problem, we have:

• a right triangle △ABC,

• the altitude to the hypotenuse is denoted AN,

• AB = 2√5 in,

• NC = 1 in.

Using the data above, we draw the following diagram:

We must compute BN, AN and AC.

To solve this problem, we will use Pitagoras Theorem, which states that:

$h^2=a^2+b^2\text{.}$

Where h is the hypotenuse, a and b the sides of a right triangle.

(I) From the picture, we see that we have two sub right triangles:

1) △ANC with sides:

• h = AC,

• a = ,NC = 1,,

• b = NA.

2) △ANB with sides:

• h = ,AB = 2√5,,

• a = BN,

• b = NA,

Replacing the data of the triangles in Pitagoras, Theorem, we get the following equations:

$\begin{cases}AC^2=1^2+NA^2, \\ (2\sqrt[]{5})^2=BN^2+NA^2\text{.}\end{cases}\Rightarrow\begin{cases}NA^2=AC^2-1, \\ NA^2=20-BN^2\text{.}\end{cases}$

Equalling the last two equations, we have:

$\begin{gathered} AC^2-1=20-BN^2.^{} \\ AC^2=21-BN^2\text{.} \end{gathered}$

(II) To find the values of AC and BN we need another equation. We find that equation applying the Pigatoras Theorem to the sides of the bigger right triangle:

3) △ABC has sides:

• h = BC = ,BN + 1,,

• a = AC,

• b = ,AB = 2√5,,

Replacing these data in Pitagoras Theorem, we have:

$\begin{gathered} \mleft(BN+1\mright)^2=(2\sqrt[]{5})^2+AC^2 \\ (BN+1)^2=20+AC^2, \\ AC^2=(BN+1)^2-20. \end{gathered}$

Equalling the last equation to the one from (I), we have:

$\begin{gathered} 21-BN^2=(BN+1)^2-20, \\ 21-BN^2=BN^2+2BN+1-20 \\ 2BN^2+2BN-40=0, \\ BN^2+BN-20=0. \end{gathered}$

(III) Solving for BN the last quadratic equation, we get two values:

$\begin{gathered} BN=4, \\ BN=-5. \end{gathered}$

Because BN is a length, we must discard the negative value. So we have:

$BN=4.$

Replacing this value in the equation for AC, we get:

$\begin{gathered} AC^2=21-4^2, \\ AC^2=5, \\ AC=\sqrt[]{5}. \end{gathered}$

Finally, replacing the value of AC in the equation of NA, we get:

$\begin{gathered} NA^2=(\sqrt[]{5})^2-1, \\ NA^2=5-1, \\ NA=\sqrt[]{4}, \\ AN=NA=2. \end{gathered}$

Answers

The lengths of the sides are:

• BN = 4 in,

• AN = 2 in,

• AC = √5 in.

7 0

1 year ago

Lisa's mom is making cookies to sell at the bake sale. She spent 12 minutes mixing the cookie batter. It took 18 minutes to bake

Llana [10]

Answer:

38 min

Step-by-step explanation:

cuz 12+8+18= 38

pls mark brainliest

8 0

3 years ago

Use the interactive to make a vertical line with the equation of x = 3. The line x = 3 has slope.

Sliva [168]

Answer:

Slope of equation x = 3 is not defined.

Step-by-step explanation:

The graph for equation $x = 3$ is attached.

As clear from the graph, x=3, is a straight line parallel to y-axis.

Slope:

Since the given equation of line is parallel to the y-axis and parallel lines have same slope.
Parallel lines have the same slope and will never intersect. Parallel lines continue, literally, forever without touching

Thus, the given equation will have the same slope as the y-axis.

The slope of y-axis is not defined.

Hence, the slope of this line is not defined.