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Nostrana [21]
3 years ago
15

A cyclist travels at 10 km/hr for 2 hours and then at 13 km/hr for 1 hour.

Mathematics
2 answers:
slavikrds [6]3 years ago
5 0

Answer:

11.5 m/s

Step-by-step explanation:

Strike441 [17]3 years ago
3 0
The average speed would be 11km/h. 10 km 1 hour 10 km another hour 13 km 1 hour. A total of 3 hours. Add the three number 10+10+13= 33. Since there are three numbers divide by 3. 33/3=11. 11 is the average speed within the three hours.
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Answer:

98.57

Step-by-step explanation:

3.5% over 100% X 102=3.43

102-3.43= 98.57

6 0
3 years ago
Multiply and simplify
aleksandr82 [10.1K]

Answer and explanation:

1. 2 × 3/10 = 6/10 = 3/5

2. 8 × 4/8 = 32/8 = 4

3. 9 × 3/9 = 27/9 = 3

4. 12 × 2/11 = 24/11 = 2 2/11

5. 3 × 5/7 = 15/7 = 2 1/7

6. 2 × 3/5 = 6/5 = 1 1/5

7. 11 × 4/8 = 44/8 = 5 4/8 = 5 1/2

8. 10 × 1/4 = 10/4 = 2 2/4 = 2 1/2

9. 5 × 1/4 = 5/4 = 1 1/4

10. 11 × 2/7 = 22/7 = 3 1/7

Hope this helps!

4 0
3 years ago
A. The seats are divided into 40 different sections thats are given in only 5 sections, what
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3 years ago
Find the x- and y-intercepts of the graph of the linear equation −x+8y=4.
Ulleksa [173]
X intercept: (-4,0)
y intercept: (0,1/2)

x-intercept is when y = 0
-x+8(0)=4
-x+0=4
x=-4

y-intercept is when x = 0
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(3squared)squared x(10cubed)squared
kiruha [24]

Hii :))

\tt {(3 ^{2} )}^{2}  \times  {(10^{3}) }^{2}  \\ \tt  = (3 \times 3) ^{2}  \times  {(10 \times 10 \times 10)}^{2}  \\   \tt \: =  {9}^{2}  \times 1000 ^{2}  \\ \tt  = (9 \times 9) \times (1000 \times 1000) \\  = \tt \:  81  \times  1000000 \\  =  \boxed{\tt \:  81000000}

__________________

\overbrace{ \underbrace{ \mathfrak{ \: \infty  \:  Carry \: on \: Learning \:  \infty }}}

ᴛʜᴇᴇxᴛʀᴀᴛᴇʀᴇꜱᴛʀɪᴀʟ

3 0
3 years ago
Read 2 more answers
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