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krok68 [10]
2 years ago
8

Determine the interval(s) on which the given function is-decreasing.

Mathematics
1 answer:
Vinil7 [7]2 years ago
6 0

A function assigns the values. The interval for which the given function will be decreasing is (-∞, -1)∪(0,∞).

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

The interval for which the given function will be decreasing is from point A to point B, and then from point C to point D. Therefore, the interval will be (-∞, -1) and (0,∞). Hence, The interval for which the given function will be decreasing is (-∞, -1)∪(0,∞).

Learn more about Function:

brainly.com/question/5245372

#SPJ1

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Jennifer has $26 less than triple the savings of Matthew. Matthew has saved $81. How much has Jennifer Saved?​
BabaBlast [244]
$81 x 3 = triple the savings = $243
$243 - $26 = what Jennifer has saved which equals = $217
I think that’s how you do it, anyways hope this helped!
6 0
3 years ago
What is the slope of the line through (-10, 1) and (0, –4)?
aleksandr82 [10.1K]

Answer:

-0.5

Step-by-step explanation:

slope = (y2-y1)/(x2-x1)

         = (-4 - 1)/(0-(-10))

         = (-5)/10

         = -0.5

3 0
3 years ago
What is the surface area of the regular pyramid below?
kkurt [141]

Answer:

648 sq units

Step-by-step explanation:

Area of the base= 12×12= 144 sq. units

Perimeter of the base=4×12= 48

Total surface area= 1/2×48×21 + 144

=648 sq units

8 0
3 years ago
Read 2 more answers
I am confused Help me.
vekshin1

about what there is no question here....?

8 0
3 years ago
A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude
bulgar [2K]

Answer:

a) 20.61%

b) 21.82%

c) 42.36%

d) 4 withdrawals

Step-by-step explanation:

This situation can be modeled with a binomial distribution, where p = probability of “success” (completing the course) equals 80%  = 0.8 and the probability of “failure” (withdrawing) equals 0.2.

So, the probability of exactly k withdrawals in 20 cases is given by

\large P(20;k)=\binom{20}{k}(0.2)^k(0.8)^{20-k}

a)

We are looking for

P(0;20)+P(0;1)+P(0;2) =  

\large \binom{20}{0}(0.2)^0(0.8)^{20}+\binom{20}{1}(0.2)^1(0.8)^{19}+\binom{20}{2}(0.2)^2(0.8)^{18}=

0.0115292150460685 + 0.0576460752303424 + 0.136909428672063 = 0.206084718948474≅ 0.2061 or 20.61%

b)

Here we want P(20;4)

\large P(20;4)=\binom{20}{4}(0.2)^4(0.8)^{16}=0.218199402\approx 0.2182=21.82\%

c)

Here we need

\large \sum_{k=4}^{20}P(20;k)=1-\sum_{k=1}^{3}P(20;k)

But we already have P(0;20)+P(0;1)+P(0;2) =0.2061 and

\large \sum_{k=1}^{3}P(20;k)=0.2061+P(20;3)=0.2061+0.205364 \approx 0.4236=42.36\%

d)

For a binomial distribution the <em>expectance </em>of “succeses” in n trials is np where p is the probability of “succes”, and the expectance of “failures” is nq, so the expectance for withdrawals in 20 students is 20*0.2 = <em>4 withdrawals.</em>

3 0
3 years ago
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