Expanding the left side gives
which gives two solutions,
and
. But if
, then
, but this number isn't real, so
is an extraneous solution. Meanwhile if
, you get
, so this solution is correct.
"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.
The area of a rectangle is A=LW, the area of a square is A=S^2.
W=S-2 and L=2S-3
And we are told that the areas of each figure are the same.
S^2=LW, using L and W found above we have:
S^2=(2S-3)(S-2) perform indicated multiplication on right side
S^2=2S^2-4S-3S+6 combine like terms on right side
S^2=2S^2-7S+6 subtract S^2 from both sides
S^2-7S+6=0 factor:
S^2-S-6S+6=0
S(S-1)-6(S-1)=0
(S-6)(S-1)=0, since W=S-2, and W>0, S>2 so:
S=6 is the only valid value for S. Now we can find the dimensions of the rectangle...
W=S-2 and L=2S-3 given that S=6 in
W=4 in and L=9 in
So the width of the rectangle is 4 inches and the length of the rectangle is 9 inches.
Answer:
it would be w7
Step-by-step explanation:
because to get w you mulitply w with 7
so all that you need to do is put the 7 next to the w
because mathematicians are known to be lazzy so they do not put the multiplication sign, instead the put it next to each other meaning that it is mulitplied
simple awnser for the simple question
Answer:
W = -L + V
Step-by-step explanation:
V = L + W
~Subtract L to both sides
V - L = W
Best of Luck!
Answer:
The quotient is 
Step-by-step explanation:
The given polynomial division is 
To perform the synthetic division we write out the coefficients and arrange them as shown.
1 -4 4 -1
<u>1 | 1 -3 1</u>
1 -3 1 0
The quotient is
The descending powers of x means from highest degree to the least
The remainder is 0
