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Zinaida [17]
2 years ago
8

5

Mathematics
1 answer:
FinnZ [79.3K]2 years ago
4 0

<u>Part 1: Finding radius</u>

The radius of a circle is defined as the distance from the center to a point on the circle's circumference.

Using the distance formula,

r=\sqrt{(-7-8)^{2}+(-1-7)^{2}}=\boxed{17}

<u>Part 2: Finding the point with x-coordinate -15</u>

Let the y coordinate of the point be y. Then, we have the point (-15, y). Substituting into the distance formula,

\sqrt{(-15-(-7))^{2}+(-1-y)^{2}}=17\\\\64+(-1-y)^{2}=289\\\\(-1-y)^{2}=225\\\\-1-y =\om 15\\\\y=\boxed{-16, 14}

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The average of six numbers is 4. If the of two of those numbers is 2, what is the average of the other four numbers?
matrenka [14]

Answer:

5

Step-by-step explanation:

total sum of the 6 numbers

= 4 ×6

= 24

sum of numbers without the two 2s

= 24 - 2(2)

= 20

average of other 4 numbers

= 20 ÷ 4

= 5

6 0
3 years ago
This is a sketch of the curve with equation y = f(x).
Katen [24]

Answer:

We have to use the formule to calculate the vertex which is: V(-b/2a;4ac-b^2/4a)

A) y=x+7 where a=1 b=0 and c=7

By replacing we have: V(0;28/4) V(0;7)

B) y=-x where a=-1 b and c=0 so V(0,0)

6 0
3 years ago
A team of three students are working on a language-learning app; they need to develop 300 micro-lessons and 300 micro-tests befo
Olegator [25]

Answer: a) 15 b)

Step-by-step explanation:

Let X be the number of days:

a)

For LESSONS:

Jordan does 10 / day ( 10*X)

Marco 5 / day ( 5*X)

Junyi 5 / day ( 5*X)

For TESTS:

Jordan does 5 / day ( 5*X)

Marco 10 / day ( 10*X)

Junyi 8 / day ( 8*X)

for each they need a total of 300

a) 10X+5X+5X=300 => 20X = 300 => X = 15 days for the lessons

b) 5X+10X+8X = 300 => 23X = 300 => X = 13.04 days for the tests

so they need 15 days to finish both tasks

now if Junyi gets sick we just eliminate his contribution

a) 10X+5X=300 => 15X = 300 => X = 20 days for the lessons

b) 5X+10X = 300 => 15X = 300 => X = 20 days for the tests

so in 20 days they will finish without him

If jordan works 10 hours a day, we just replace him with 10/24

a) 10(10/24)+5X+5X= 300 => X = 29.58 days for the lessons

b) 5(10/24)+10X+8X = 300 => X = 16.51 days for the tests

so at the end to complete both tasks they need 29.58 days

4 0
3 years ago
3 pieces of wood have a total length of 32 m. The second piece is twice the size of the first and the third piece is 2 more mete
andreev551 [17]

Answer:

X + Y + Z = 32

X2 = Y

X3 + 2 = Z

X + X2 + X3 + 2 = 32

Make X alone

There is a 2 so we subtract 2 from both sides

X + X2 + X3 = 30

Add the X's up

X + X2 + X3 = X6

X6 = 30

Divide by 6

30 / 6 = 5

You are left with X=5

The first piece of wood has a length of 5

5 x 2 = 10

The second piece has a value of 10

5 x 3 + 2 = 17

The third piece is 17

Hope this helps. If you have any questions you may ask.

Step-by-step explanation:

5 0
3 years ago
Identify the perimeter and area of a square with diagonal length 11in. Give your answer in simplest radical form. HELP PLEASE!!
Nataliya [291]

Answer:

  • Perimeter = 22*sqrt(2)
  • Area = 60.5 inches
  • D

Step-by-step explanation:

Remark

You need 2 facts.

  1. A square has 4 equal sides.
  2. It contains (by definition) 1 right angle but since we are not including and statement about parallel sides, it needs 4 right angles.

That means you can use the Pythagorean Theorem.

If one side of a square is a then the 1 after it is a as well.

Formula

  • a^2 + a^2 = c^2
  • 2a^2 = c^2

Givens

  • c = 11

Solution

  • 2a^2 = 11^2
  • 2a^2 = 121                    Divide by 2
  • a^2 = 121/2                  Take the square root of both sides
  • sqrt(a^2) = sqr(121/2)    
  • a = 11/sqrt(2)                Rationalize the denominator
  • a = 11 * sqrt(2)/[sqrt(2) * sqrt(2)]
  • a = 11 * sqrt(2) / 2

<em><u>Perimeter</u></em>

P = 4s

  • P = 4*11*sqrt(2)/2
  • P = 44*sqrt(2)/2
  • P = 22*sqrt(2)

You don't need the area. The answer is D

<em><u>Area</u></em>

  • Area = s^2
  • Area = (11*sqrt(2)/2 ) ^2
  • Area = 121 * 2 / 4
  • Area = 60.5


8 0
3 years ago
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