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jekas [21]
2 years ago
15

With unique examples of your own let’s discuss the number of solutions possible (0, 1, 2, 3, 4) to a system of equations that in

clude a conic section.
Mathematics
1 answer:
chubhunter [2.5K]2 years ago
8 0

The number of solutions possible to a system of equations that include a conic section depends on the type of equations involved

<h3>How to determine the number of solutions?</h3>

A system of equation that has a conic section may or may not have solutions.

It would have a solution if the equations intersect, when plotted on a graph and it would not, if otherwise

A conic section can be any of:

  • Parabola
  • Ellipse
  • Hyperbola
  • Circle

<u>Example 1: No solution</u>

Consider the following system of equations

  • y = x² - 10 --- parabola equation
  • (x - 1)² + (y - 2)² = 5 --- circle

The above system of equations has no solution because they do not intersect when plotted on a graph (see graph 1)

<u>Example 2: One solution</u>

Consider the following system of equations

  • x = 2 --- linear equation
  • y = x² - 10 --- parabola

The above system of equations has one solution because they intersect at one point (see graph 2)

<u>Example 3: One solution</u>

Consider the following system of equations

  • y = 2x + 1 --- linear equation
  • y = x² - 10 --- circle

The above system of equations has two solutions because they intersect at two points (see graph 3)

The above examples imply that a system of equations that involves conic section can have as many solutions as possible.

The number of solutions depends on the type of equations involved

The attached graphs illustrate how a system of equations can have 0 to 4 solutions

Read more about system of equations at:

brainly.com/question/14323743

#SPJ1

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15 POINTSSS<br> Need Anwsered Asap!
german
The equation we will use here is A^2+B^2=C^2, which is also know as the Pythagorean Theorem.
The given values are 6 and 9, where they can represent any value, there true values in the equation would be 36(6), and 81(9), so you must select a value that makes the equation true, given the constraints.

with that being said 3, doesnt work because
·36(6)+9(3)≠81(9)
·9(3)+81(9)≠36(6)
·36(6)+81(9)≠9(3)

10 doesnt work either because
·36(6)+81(9)≠100(10)
·81(9)+100(10)≠36(6)
·100(10)+36(6)≠81(9)

12 doesnt work either because 
·144(12)+36(6)≠81(9)
·36(6)+81(6)≠144(12)
·81(9)+144(12)≠36(6)

If you see where this is going you would know that there is no valid solution here, however rounding is always a possibility, when you actually do the math 81(9)+36(6)=117, and when squared you get your answer of 10.8, and the closest answer is 10, there fore your answer would be 10

-I hope this is the answer you are looking for, feel free to post your questions on brainly at any time.



5 0
3 years ago
Use addition to solve the linear system of equations. Include all of your work in your final answer.
nadezda [96]
You just have to add one eqaution to another :
-x + x -y + 2y = 7 + 7
y = 14
Then apply y = 14 to one of the equations :
eg: x + 2(14) = 7
x + 28 = 7
x = - 21
The awnser is x= -21 y= 14
I hope i awnsered your question
3 0
3 years ago
88/1 in simplest form
Pavlova-9 [17]

Answer:

88

Step-by-step explanation:

Divide the numerator by the denominator.

88 ÷ 1 = 88

5 0
3 years ago
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