It’s -63 all you would be multiple like normal 63 which then you put a negative symbol on front
First find the slope of the line so change in y over change in x so 4-2/1-2 which is 2/-1 so -2 is your slope then plug that as well as a point from above to find your y intercept so y=mx+b 2=-2(2)+ b then you have 2=-4+b then add 4 to each side and you find b is six then you make ur equation from your slope and y int(b) y=-2x+6
Answer:
<h3>
(2, 124)</h3>
Step-by-step explanation:
f(x) = a(x - h)² + k - the vertex form of the equation of the parabola with vertex (h, k)
![f(x) = -16x^2+ 64x + 80\\\\f(x) = -16(x^2- 4x) + 80\\\\f(x) = -16(\underline {x^2-2\cdot2x\cdot2+2^2}-2^2) + 80\\\\f(x) = -16\big[(x-2)^2-4\big] + 80\\\\f(x) = -16(x-2)^2+64 + 80\\\\\bold{f(x)=-16(x-2)^2+124\quad\implies\quad h=2\,,\quad k=124}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20-16x%5E2%2B%2064x%20%2B%2080%5C%5C%5C%5Cf%28x%29%20%3D%20-16%28x%5E2-%204x%29%20%2B%2080%5C%5C%5C%5Cf%28x%29%20%3D%20-16%28%5Cunderline%20%7Bx%5E2-2%5Ccdot2x%5Ccdot2%2B2%5E2%7D-2%5E2%29%20%2B%2080%5C%5C%5C%5Cf%28x%29%20%3D%20-16%5Cbig%5B%28x-2%29%5E2-4%5Cbig%5D%20%2B%2080%5C%5C%5C%5Cf%28x%29%20%3D%20-16%28x-2%29%5E2%2B64%20%2B%2080%5C%5C%5C%5C%5Cbold%7Bf%28x%29%3D-16%28x-2%29%5E2%2B124%5Cquad%5Cimplies%5Cquad%20h%3D2%5C%2C%2C%5Cquad%20k%3D124%7D)
<u>The vertex is </u><u>(2, 124)</u>
7=2x + 15 2x= -8 x= -4
<span>8= 3x 8= 3x+0 3x +-8 3(-4) +-8 -12 - 8 </span>
<span>Final Answer -20</span>
