You can do this by drawing one line through parallel to PQS to meet RQ at T
Now calculate length of RT:-
cos 70 = RT / 70 giving RT = 23.94m
sin 70 = ST/70 giving ST = 65.78 m
draw a line from S perpendicular to PQ to meet PQ at U.
PU = 110 - 65.78 = 44.22 m
tan 50 = SU / 44.22 giving SU = 52.70 m
TQ = SU = 52.70 m
So x = TQ + RT = 52.70 + 23.94 = 76.6 m to 1 dec place.
Answer:
600
Step-by-step explanation:
Answer:
Sure!
Step-by-step explanation:
Answer:
2000000 bricks
Step-by-step explanation:
The computation of the number of bricks to be used is shown below:
The Volume of brick is
= (15 × 8 × 5)cm^3
= 600 cm^3
And, the Volume of wall is
= (1500 × 1000 × 800)cm^3
= 1200000000 cm^3
Now Bricks needed is
= 1200000000 cm^3 ÷ 600cm^3
= 2000000 bricks
