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klemol [59]
3 years ago
8

Solve the compound inequality 9 + 3n >= 6 or 5n < 25.

Mathematics
1 answer:
babymother [125]3 years ago
4 0
9+3n \geq 6 \ \lor \ 5n\ \textless \ 25 \\&#10;3n \geq 6-9 \ \lor \ n \ \textless \ \frac{25}{5} \\&#10;3n \geq -3 \ \lor \ n \ \textless \ 5 \\&#10;n \geq \frac{-3}{3} \\&#10;n \geq -1 \\ \\&#10;\boxed{n \geq -1 \hbox{ or } n\ \textless \ 5} \\ \\&#10;\hbox{answer C}
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What is the angle, in degrees, if the Area is 180 square miles and the radius is 42,240 feet?
Savatey [412]

Step-by-step explanation:

the area of a circle (all 360°) is

pi×r²

with r being the radius.

the area of a circle segment is just the corresponding fraction of the whole circle.

so the area of a segment of x degrees is

pi×r² × x/360

in our case we know

pi×42240² × x/360 = 180 mi²

we also know that there are 5280 ft in 1 mile.

so, the radius is actually

42240 / 5280 = 8 miles

and therefore our equation resulting in mi² has to use miles and not ft and has to look that way :

pi×8² × x/360 = 180 mi²

pi×64 × x/360 = 180

pi×64 × x = 180×360

pi×x = 180×360/64 = 1012.5

x = 1012.5/pi = 322.2887598...°

so, the angle of the segment of a circle with the area of 180 mi² and the radius of 8 mi is 322.2887598...°

5 0
2 years ago
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Alona [7]

Answer:

x= -48 y =48

Step-by-step explanation:

-46 and 2 is -48 numbers away

3 0
3 years ago
Grace wants to buy gumballs out of a vending machine in an airport. Two gumballs cost $0.80. If Grace uses exact change, in how
devlian [24]
She could use the following methods:
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3 years ago
Please answer this!!!!
Zolol [24]

Answer:

im not very sure but i believe that it is (40,4)

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2 years ago
Read 2 more answers
140 subtracted from the square of a number the result is three times the number find the negative solution
natima [27]

Answer:

Suppose~that~the~number~is~x.\\According~to~question,\\x^2-140=3x\\or, x^2-3x-140=0\\From~the~quadratic~formula,\\x = \frac{-(-3)+\sqrt{(-3)^2-4(1)(-140)} }{2(1)} ~and ~x= \frac{-(-3)-\sqrt{(-3)^2-4(1)(-140)} }{2(1)} \\or, x = \frac{3+\sqrt{9+560} }{2}~and~x=\frac{3-\sqrt{9+569} }{2}\\or, x = \frac{3+\sqrt{569} }{2}~and~x=\frac{3-\sqrt{569} }{2}\\So,~the~required~negative~number~is~\frac{3-\sqrt{569} }{2}.

5 0
3 years ago
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