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4 years ago

8

Solve the compound inequality 9 + 3n >= 6 or 5n < 25.

1 answer:

babymother [125]4 years ago

4 0

$9+3n \geq 6 \ \lor \ 5n\ \textless \ 25 \\
3n \geq 6-9 \ \lor \ n \ \textless \ \frac{25}{5} \\
3n \geq -3 \ \lor \ n \ \textless \ 5 \\
n \geq \frac{-3}{3} \\
n \geq -1 \\ \\
\boxed{n \geq -1 \hbox{ or } n\ \textless \ 5} \\ \\
\hbox{answer C}$

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2x – 3 > 2(x-5) <br> What’s the answer

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Answer:

N/A

Step-by-step explanation:

2x - 3 > 2(x-5)

2x - 3 > 2x - 10

2x - 2x > -10 + 3

0 > -7

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3 years ago

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3 years ago

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What is the equation of the circle with a center of (8,-2) and a point on the circle of (3,-6)

Artyom0805 [142]

Answer:

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Step-by-step explanation:

3 0

3 years ago

Consider the surface defined by the equation x3 + y3 + z3 = 3xyz. Use implicit differ- ∂z entiation to find ∂x. (Note z is not a

Aloiza [94]

Answer:

$\frac{∂z}{∂x}=\frac{(3yz-3x^{2})}{3z^{2} -3xy}$

Step-by-step explanation:

Given equation is $x^{3}+y^{3}+z^{3}=3xyz$ ………………(1)

we use derivative formula $\frac{d}{dx}(x^{n}) = n x^{n-1}$

$\frac{d}{dx}(x^{3)} = 3 x^{2}$

$\frac{d}{dx}(z^{3)} = 3 z^{2}$

And also apply 'u v' formula

$\frac{d}{dx}(uv}) = u\frac{d}{dx}(v)+v\frac{d}{dx}(u)$

Differentiating equation (1) partially with respective to 'x' , we treated 'y' as constant.

$(3x^{2} +0+3z^{2}\frac{∂z}{∂x}) =3y(x\frac{∂z}{∂x}+z(1))$ ( here y treated as constant so the derivative of constant function is zero in addition but in multiplication the constant is keep as like 'y').

on simplification , we get

$(3x^{2} +0+3z^{2}\frac{∂z}{∂x}) =(3yx\frac{∂z}{∂x}+3yz)$

again simplification, we get

$3z^{2}\frac{∂z}{∂x}- 3yx\frac{∂z}{∂x}=3yz-3x^{2}$

taking common ' $\frac{∂z}{∂x}$ on left on side , we get

$(3z^{2}- 3yx)\frac{∂z}{∂x}=3yz-3x^{2}$

dividing ' $(3z^{2}- 3yx)$ on both sides, we get

$\frac{∂z}{∂x}=\frac{(3yz-3x^{2})}{3z^{2} -3xy}$

<u>Final answer</u>:-

$\frac{∂z}{∂x}=\frac{(3yz-3x^{2})}{3z^{2} -3xy}$

6 0

4 years ago

PLEASE HELP QUICKLY IF YOU CAN!

Anastasy [175]

Answer:

6 - $(\frac{2}{3} )^{2} =$ $\frac{50}{9}$

3² - $(\frac{2}{3} )=$ $8\frac{1}{3}$

7 - $(\frac{1}{2} )^{3}$ = $\frac{55}{8}$

Step-by-step explanation:

1. 6 - $(\frac{2}{3} )^{2}$

First, apply the exponent to 2/3. Because it's to the second power, multiply 2/3 by itself.

$(\frac{2}{3} )^{2}=\frac{4}{9}$

6 - $\frac{4}{9}$

Now, subtract.

6 - $\frac{4}{9}$ = $\frac{50}{9}$

------------------------------------------

2. 3² - $\frac{2}{3}$

First, apply the exponent.

3² = 9

9 - $\frac{2}{3}$

Now, subtract.

9 - $\frac{2}{3}=\frac{25}{3}$

$\frac{25}{3} =8\frac{1}{3}$

------------------------------------------

3. 7 - $(\frac{1}{2} )^{3}$

First, apply the exponent.

$(\frac{1}{2} )^{3}$ = $\frac{1}{8}$

7 - $\frac{1}{8}$

Now, subtract.

7 - $\frac{1}{8}=\frac{55}{8}$

hope this helps!

4 0

2 years ago